Plan and Solve What unknown are you trying to calculate? Amount of energy absorbed, Q What formula contains the given quantity and the unknown? Q = mcAT = mc(T-T₁) Substitute the known values and solve. Q=(25.0 g)(0.48 cal/g-°C)(0.0°C - (-10.0°C)) = 120 cal Look Back and Check Is your answer reasonable? Yes, the sign shows that heat was absorbed and the unit, c proper unit for energy. Math Practice Note that
Plan and Solve What unknown are you trying to calculate? Amount of energy absorbed, Q What formula contains the given quantity and the unknown? Q = mcAT = mc(T-T₁) Substitute the known values and solve. Q=(25.0 g)(0.48 cal/g-°C)(0.0°C - (-10.0°C)) = 120 cal Look Back and Check Is your answer reasonable? Yes, the sign shows that heat was absorbed and the unit, c proper unit for energy. Math Practice Note that
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![**Plan and Solve**
**What unknown are you trying to calculate?**
Amount of energy absorbed, Q
**What formula contains the given quantity and the unknown?**
\[ Q = mc\Delta T = mc(T_f - T_i) \]
**Substitute the known values and solve.**
\[ Q = (25.0 \, \text{g})(0.48 \, \text{cal/g°C})(0.0°C - (-10.0°C)) = 120 \, \text{cal} \]
**Look Back and Check**
**Is your answer reasonable?**
Yes, the sign shows that heat was absorbed and the unit, calories, is a proper unit for energy.
---
**Math Practice**
On a separate sheet of paper, solve the following problems. Note that quantity of heat energy required to change the phase of a substance is given by the following equation: \( Q = mL \), where \( Q \) is the heat required, \( m \) is the mass, and \( L \) is the heat of fusion or vaporization.
1. **How much energy is absorbed when 25.0 g of ice at 0.0°C melts to form water at 0.0°C?** The heat of fusion of ice is 80 cal/g.
2. **How much energy is absorbed when the water at 0.0°C in Question 1 is heated to 100.0°C?** The specific heat of water is 1.0 cal/g°C.
3. **How much energy is absorbed when the water at 100.0°C in Question 2 vaporizes to 100.0°C?** The heat of vaporization of water is 540 cal/g.
4. **The steam in Question 3 is used to melt ice. How much ice will be melted by the energy released by the condensation of the steam at 100.0°C?**
---
(Note: The handwritten note at the bottom says "#4 I please," indicating a request for help with question 4.)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3570f510-88cc-47e8-8abe-e1329d4d401b%2F748f256e-0706-495f-b568-80d7eacb84ce%2Fj4zkfq_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Plan and Solve**
**What unknown are you trying to calculate?**
Amount of energy absorbed, Q
**What formula contains the given quantity and the unknown?**
\[ Q = mc\Delta T = mc(T_f - T_i) \]
**Substitute the known values and solve.**
\[ Q = (25.0 \, \text{g})(0.48 \, \text{cal/g°C})(0.0°C - (-10.0°C)) = 120 \, \text{cal} \]
**Look Back and Check**
**Is your answer reasonable?**
Yes, the sign shows that heat was absorbed and the unit, calories, is a proper unit for energy.
---
**Math Practice**
On a separate sheet of paper, solve the following problems. Note that quantity of heat energy required to change the phase of a substance is given by the following equation: \( Q = mL \), where \( Q \) is the heat required, \( m \) is the mass, and \( L \) is the heat of fusion or vaporization.
1. **How much energy is absorbed when 25.0 g of ice at 0.0°C melts to form water at 0.0°C?** The heat of fusion of ice is 80 cal/g.
2. **How much energy is absorbed when the water at 0.0°C in Question 1 is heated to 100.0°C?** The specific heat of water is 1.0 cal/g°C.
3. **How much energy is absorbed when the water at 100.0°C in Question 2 vaporizes to 100.0°C?** The heat of vaporization of water is 540 cal/g.
4. **The steam in Question 3 is used to melt ice. How much ice will be melted by the energy released by the condensation of the steam at 100.0°C?**
---
(Note: The handwritten note at the bottom says "#4 I please," indicating a request for help with question 4.)
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