Pl anet # 1 M3 M1 ..... .... Planet # 2 Planet # 3 Planet #2 (mass M2) and planet #3 (mass M3) are separated by distance R. Planet #1 of mass M, is directly between these two planets. What is the force F12 on planet #1 due to the gravitational force of planet #2 at the position r in the above figure? O F12 = GM,M2 / 3 O F12 = GM1 / r? O F12 = GM1M2/r O F12 = GM1M2 /? O F12 = GM,M2r? %3D %3D !3! %3D %3D Submit Answer Tries 0/2 What is the direction of the force F12? toward planet 1 perpendicular to the line joining planet 1 and planet 2 toward planet 3 toward planet 2 Submit Answer Tries 0/2 What is the force F13 on planet #1 due to the gravitational force of planet #3 at the position r in the above figure? F13 = GM1M3 / R? %3D F13 = GM1M3(R-r)² F13 = GM1M3/ (R-r) %3D %3D F13 = GM1M3/ r2 F13 = GM1M3 / (R-r)2 Submit Answer Tries 0/2 What is the direction of the force F13? toward planet 2 toward planet 1 perpendicular to the line joining planet 1 and planet 3 O toward planet 3
Pl anet # 1 M3 M1 ..... .... Planet # 2 Planet # 3 Planet #2 (mass M2) and planet #3 (mass M3) are separated by distance R. Planet #1 of mass M, is directly between these two planets. What is the force F12 on planet #1 due to the gravitational force of planet #2 at the position r in the above figure? O F12 = GM,M2 / 3 O F12 = GM1 / r? O F12 = GM1M2/r O F12 = GM1M2 /? O F12 = GM,M2r? %3D %3D !3! %3D %3D Submit Answer Tries 0/2 What is the direction of the force F12? toward planet 1 perpendicular to the line joining planet 1 and planet 2 toward planet 3 toward planet 2 Submit Answer Tries 0/2 What is the force F13 on planet #1 due to the gravitational force of planet #3 at the position r in the above figure? F13 = GM1M3 / R? %3D F13 = GM1M3(R-r)² F13 = GM1M3/ (R-r) %3D %3D F13 = GM1M3/ r2 F13 = GM1M3 / (R-r)2 Submit Answer Tries 0/2 What is the direction of the force F13? toward planet 2 toward planet 1 perpendicular to the line joining planet 1 and planet 3 O toward planet 3
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![### Explanation of Gravitational Forces Between Planets
The scenario depicts three planets interacting through gravitational forces:
- **Planet #1** with mass \( M_1 \)
- **Planet #2** with mass \( M_2 \)
- **Planet #3** with mass \( M_3 \)
Planet #2 and Planet #3 are separated by a distance \( R \). Planet #1 is at position \( r \) between them.
#### Diagram Overview
- Planet #3 is on the left, shown in red, followed by planet #1 in green, and planet #2 in blue on the right.
- The arrow indicates the direction from planet #3 through planet #1 to planet #2.
### Questions and Explanations
1. **What is the force \( F_{12} \) on planet #1 due to the gravitational force of planet #2 at the position \( r \)?**
Multiple choice options:
- \( F_{12} = \frac{GM_1M_2}{r^3} \)
- \( F_{12} = \frac{GM_1}{r^2} \)
- \( F_{12} = \frac{GM_1M_2}{r} \)
- \( F_{12} = \frac{GM_1M_2}{r^2} \) [Correct choice]
- \( F_{12} = GM_1M_2r^2 \)
2. **What is the direction of the force \( F_{12} \)?**
Choices:
- Toward planet 1
- Perpendicular to the line joining planet 1 and planet 2
- Toward planet 3
- Toward planet 2 [Correct choice]
3. **What is the force \( F_{13} \) on planet #1 due to the gravitational force of planet #3 at the position \( r \)?**
Multiple choice options:
- \( F_{13} = \frac{GM_1M_3}{R^2} \)
- \( F_{13} = \frac{GM_1M_3(R-r)^2}{R} \)
- \( F_{13} = \frac{GM_1M_3}{(R-r)} \)
- \( F_{13} = \frac{GM_1](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa50e57d1-2bd6-427e-801e-187552a1e482%2Fe906be81-514c-4710-a8c4-42f406408b81%2Fig20lr_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Explanation of Gravitational Forces Between Planets
The scenario depicts three planets interacting through gravitational forces:
- **Planet #1** with mass \( M_1 \)
- **Planet #2** with mass \( M_2 \)
- **Planet #3** with mass \( M_3 \)
Planet #2 and Planet #3 are separated by a distance \( R \). Planet #1 is at position \( r \) between them.
#### Diagram Overview
- Planet #3 is on the left, shown in red, followed by planet #1 in green, and planet #2 in blue on the right.
- The arrow indicates the direction from planet #3 through planet #1 to planet #2.
### Questions and Explanations
1. **What is the force \( F_{12} \) on planet #1 due to the gravitational force of planet #2 at the position \( r \)?**
Multiple choice options:
- \( F_{12} = \frac{GM_1M_2}{r^3} \)
- \( F_{12} = \frac{GM_1}{r^2} \)
- \( F_{12} = \frac{GM_1M_2}{r} \)
- \( F_{12} = \frac{GM_1M_2}{r^2} \) [Correct choice]
- \( F_{12} = GM_1M_2r^2 \)
2. **What is the direction of the force \( F_{12} \)?**
Choices:
- Toward planet 1
- Perpendicular to the line joining planet 1 and planet 2
- Toward planet 3
- Toward planet 2 [Correct choice]
3. **What is the force \( F_{13} \) on planet #1 due to the gravitational force of planet #3 at the position \( r \)?**
Multiple choice options:
- \( F_{13} = \frac{GM_1M_3}{R^2} \)
- \( F_{13} = \frac{GM_1M_3(R-r)^2}{R} \)
- \( F_{13} = \frac{GM_1M_3}{(R-r)} \)
- \( F_{13} = \frac{GM_1
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