pitiosge ertl a54 pll 81.A bns noituloa ent l HA 1.02grams of Mg was reacted with excess 1 M HCI (ag) (255.0 grams) in a coffee-cup calorimeter. T of the solution rose from 22.0°C to 41.6°C. Calculate the Change in heat of the reaction. C= 3.91 J g °C o vaneb erlt as Imip 00.eaU (p) (p)
pitiosge ertl a54 pll 81.A bns noituloa ent l HA 1.02grams of Mg was reacted with excess 1 M HCI (ag) (255.0 grams) in a coffee-cup calorimeter. T of the solution rose from 22.0°C to 41.6°C. Calculate the Change in heat of the reaction. C= 3.91 J g °C o vaneb erlt as Imip 00.eaU (p) (p)
Chemistry by OpenStax (2015-05-04)
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Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
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Chapter5: Thermochemistry
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Problem 27E: The addition of 3.15 g of Ba(OH)28H2O to a solution of 1.52 g of NH4SCN in loo g of water in a...
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Transcribed Image Text:pitiosge ertl a54 pll 81.A bns noituloa ent l HA
1.02grams of Mg was reacted with excess 1 M HCI (ag) (255.0 grams) in a coffee-cup
calorimeter. T of the solution rose from 22.0°C to 41.6°C. Calculate the Change in heat
of the reaction. C= 3.91 J g °C
o vaneb erlt as Imip 00.eaU
(p)
(p)
Expert Solution
Step 1
We will use the formula,
q=mc
Where,
q= change in heat
c=specific heat
= change in temperature.
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