pitiosge ertl a54 pll 81.A bns noituloa ent l HA 1.02grams of Mg was reacted with excess 1 M HCI (ag) (255.0 grams) in a coffee-cup calorimeter. T of the solution rose from 22.0°C to 41.6°C. Calculate the Change in heat of the reaction. C= 3.91 J g °C o vaneb erlt as Imip 00.eaU (p) (p)
pitiosge ertl a54 pll 81.A bns noituloa ent l HA 1.02grams of Mg was reacted with excess 1 M HCI (ag) (255.0 grams) in a coffee-cup calorimeter. T of the solution rose from 22.0°C to 41.6°C. Calculate the Change in heat of the reaction. C= 3.91 J g °C o vaneb erlt as Imip 00.eaU (p) (p)
Chapter6: Thermochemistry
Section: Chapter Questions
Problem 104AE
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
Transcribed Image Text:pitiosge ertl a54 pll 81.A bns noituloa ent l HA
1.02grams of Mg was reacted with excess 1 M HCI (ag) (255.0 grams) in a coffee-cup
calorimeter. T of the solution rose from 22.0°C to 41.6°C. Calculate the Change in heat
of the reaction. C= 3.91 J g °C
o vaneb erlt as Imip 00.eaU
(p)
(p)
Expert Solution

Step 1
We will use the formula,
q=mc
Where,
q= change in heat
c=specific heat
= change in temperature.
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