**Angle of Refraction in an Equilateral Triangular Prism** **Problem Statement:** Light in air is initially traveling parallel to the face AC of an equilateral triangular prism, as shown in the figure. The prism is made of glass with an index of refraction of 1.52. If the light does not strike the face AC, what is the angle between the ray as it leaves the prism at face BC and the surface normal? **Answer Choices:** a) 19° b) 59° c) 55° d) 83° e) 27° **Explanation:** An equilateral triangular prism has internal angles of 60 degrees. As light travels parallel to face AC, it strikes face AB at an angle of incidence relative to the normal. After refracting through the glass prism, the light emerges from face BC. Calculate the angle at which the light exits the prism using Snell's Law and geometric principles. **Figure Description:** The provided diagram is a sketch of an equilateral triangle labeled as follows: - Point A at the bottom-left corner, - Point B at the top, - Point C at the bottom-right corner. An arrow pointing from left to right toward side AB represents the light ray entering the prism. To determine the angle of refraction, Snell’s Law and the geometry of the prism are used. By analyzing the light’s path within the prism and applying relevant principles, the correct angle of refraction is identified from the given options. **Diagrams and Graphs:** - Equilateral triangle with sides labeled and the path of the light ray indicated by the arrow for visual understanding. - Angle of incidence and refraction calculations illustrate the phenomena. The process involves multiple steps including calculating the angle of incidence, using the index of refraction, and ultimately determining the exit angle in relation to the normal to the surface.

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Please write given, diagram, reasoning, and steps.

**Angle of Refraction in an Equilateral Triangular Prism**

**Problem Statement:**

Light in air is initially traveling parallel to the face AC of an equilateral triangular prism, as shown in the figure. The prism is made of glass with an index of refraction of 1.52. If the light does not strike the face AC, what is the angle between the ray as it leaves the prism at face BC and the surface normal?

**Answer Choices:**
a) 19°
b) 59°
c) 55°
d) 83°
e) 27°

**Explanation:**

An equilateral triangular prism has internal angles of 60 degrees. As light travels parallel to face AC, it strikes face AB at an angle of incidence relative to the normal. After refracting through the glass prism, the light emerges from face BC. Calculate the angle at which the light exits the prism using Snell's Law and geometric principles.
 
**Figure Description:**

The provided diagram is a sketch of an equilateral triangle labeled as follows:
- Point A at the bottom-left corner,
- Point B at the top,
- Point C at the bottom-right corner.

An arrow pointing from left to right toward side AB represents the light ray entering the prism.

To determine the angle of refraction, Snell’s Law and the geometry of the prism are used. By analyzing the light’s path within the prism and applying relevant principles, the correct angle of refraction is identified from the given options.

**Diagrams and Graphs:**
- Equilateral triangle with sides labeled and the path of the light ray indicated by the arrow for visual understanding.
- Angle of incidence and refraction calculations illustrate the phenomena.

The process involves multiple steps including calculating the angle of incidence, using the index of refraction, and ultimately determining the exit angle in relation to the normal to the surface.
Transcribed Image Text:**Angle of Refraction in an Equilateral Triangular Prism** **Problem Statement:** Light in air is initially traveling parallel to the face AC of an equilateral triangular prism, as shown in the figure. The prism is made of glass with an index of refraction of 1.52. If the light does not strike the face AC, what is the angle between the ray as it leaves the prism at face BC and the surface normal? **Answer Choices:** a) 19° b) 59° c) 55° d) 83° e) 27° **Explanation:** An equilateral triangular prism has internal angles of 60 degrees. As light travels parallel to face AC, it strikes face AB at an angle of incidence relative to the normal. After refracting through the glass prism, the light emerges from face BC. Calculate the angle at which the light exits the prism using Snell's Law and geometric principles. **Figure Description:** The provided diagram is a sketch of an equilateral triangle labeled as follows: - Point A at the bottom-left corner, - Point B at the top, - Point C at the bottom-right corner. An arrow pointing from left to right toward side AB represents the light ray entering the prism. To determine the angle of refraction, Snell’s Law and the geometry of the prism are used. By analyzing the light’s path within the prism and applying relevant principles, the correct angle of refraction is identified from the given options. **Diagrams and Graphs:** - Equilateral triangle with sides labeled and the path of the light ray indicated by the arrow for visual understanding. - Angle of incidence and refraction calculations illustrate the phenomena. The process involves multiple steps including calculating the angle of incidence, using the index of refraction, and ultimately determining the exit angle in relation to the normal to the surface.
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