Use the following information to answer the next question. Three identical positive charges are arranged as shown. 1. The net electric force on Q2 is mostly directed 1. B. D.

Q: This second answer is still incorrect.  Would there be another way to figure this out?   Thanks

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Q: RI = 670 0 %3D R2 = 690 Q R3 = 690 0 R4 = 840 0 R5 = 760 Q R6 = 330 Q R7 = 670 0 R8 = 270 Q VI = 9 V

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Q: so how do we get the an

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Q: I am stuck on these calculations. Thank you.

A: (a) using equation (1) above equation can be solved.

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