Part 2 - Inelastic collision Q6 to Q10 are based on the following graph that shows the angular velocity as a function of time for an inelastic collision between two discs, similar to the collision done in Part 2 of your lab. Inelastic collision 50- 40- Linear Fit for: Data Set | Ang. velocity omega = mt+b m (Slope): -0.5269 rad/s/s Statistics for: Data Set | Ang. velocity min: 20.81 at 10.69 max: 41.91 at 9.963 b (Y-Intercept): 47.10 rad/s Correlation: -0.9983 RMSE: 0.06649 rad/s 30- Linear Fit for: Data Set | Ang. velocity omega = mt+b m (Slope): -0.2070 rad/s/s b (Y-Intercept): 22.88 rad/s Correlation: -0.9744 RMSE: 0.1089 rad/s 20- 10- 10 15 20 (5.72, 19.03) (At:22.00 Ay:0.00) Time (s) Ang. velocity (rad/s) 8- Using the graph for the inelastic collision shown above, what is the value of the angular speed (in rad/s) of the system just after the collision? Round your answer to 2 decimal places. Your Answer: Answer Using the graph for the inelastic collision shown above, calculate the angular momentum (in g-m2/s) of the system just before the collision. Use the moment of inertia (in units g-m2) that is calculated from the mass and radius of the disc(s) (like you did for Q1). Round your answer to 5 decimal places. Your Answer: Answer

icon
Related questions
Question
Part 2 - Inelastic collision
Q6 to Q10 are based on the following graph that shows the angular velocity as a
function of time for an inelastic collision between two discs, similar to the collision
done in Part 2 of your lab.
Inelastic collision
50-
40-
Linear Fit for: Data Set | Ang. velocity
omega = mt+b
m (Slope): -0.5269 rad/s/s
Statistics for: Data Set | Ang. velocity
min: 20.81 at 10.69 max: 41.91 at 9.963
b (Y-Intercept): 47.10 rad/s
Correlation: -0.9983
RMSE: 0.06649 rad/s
30-
Linear Fit for: Data Set | Ang. velocity
omega = mt+b
m (Slope): -0.2070 rad/s/s
b (Y-Intercept): 22.88 rad/s
Correlation: -0.9744
RMSE: 0.1089 rad/s
20-
10-
10
15
20
(5.72, 19.03) (At:22.00 Ay:0.00)
Time (s)
Ang. velocity (rad/s)
8-
Transcribed Image Text:Part 2 - Inelastic collision Q6 to Q10 are based on the following graph that shows the angular velocity as a function of time for an inelastic collision between two discs, similar to the collision done in Part 2 of your lab. Inelastic collision 50- 40- Linear Fit for: Data Set | Ang. velocity omega = mt+b m (Slope): -0.5269 rad/s/s Statistics for: Data Set | Ang. velocity min: 20.81 at 10.69 max: 41.91 at 9.963 b (Y-Intercept): 47.10 rad/s Correlation: -0.9983 RMSE: 0.06649 rad/s 30- Linear Fit for: Data Set | Ang. velocity omega = mt+b m (Slope): -0.2070 rad/s/s b (Y-Intercept): 22.88 rad/s Correlation: -0.9744 RMSE: 0.1089 rad/s 20- 10- 10 15 20 (5.72, 19.03) (At:22.00 Ay:0.00) Time (s) Ang. velocity (rad/s) 8-
Using the graph for the inelastic collision shown above, what is the value of the
angular speed (in rad/s) of the system just after the collision? Round your answer to
2 decimal places.
Your Answer:
Answer
Using the graph for the inelastic collision shown above, calculate the angular
momentum (in g-m2/s) of the system just before the collision. Use the moment of
inertia (in units g-m2) that is calculated from the mass and radius of the disc(s) (like
you did for Q1). Round your answer to 5 decimal places.
Your Answer:
Answer
Transcribed Image Text:Using the graph for the inelastic collision shown above, what is the value of the angular speed (in rad/s) of the system just after the collision? Round your answer to 2 decimal places. Your Answer: Answer Using the graph for the inelastic collision shown above, calculate the angular momentum (in g-m2/s) of the system just before the collision. Use the moment of inertia (in units g-m2) that is calculated from the mass and radius of the disc(s) (like you did for Q1). Round your answer to 5 decimal places. Your Answer: Answer
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps

Blurred answer
Similar questions
  • SEE MORE QUESTIONS