A Content Take Test: Q2 Culminating PeTa - x O Messenger L PHYS1 - Google Drive + A ust.blackboard.com/webapps/assessment/take/launch.jsp?course_assessment_id=_255397_1&course_id=_122252_1&content_id= 4246228_1&step=null * Question Completion Status: 1 2 3 4 5 6 A moving electron has a Kinetic Energy K1. After a net amount of work is done on it, the electron is moving one-quarter as fast in the opposite direction. What is the work done W in terms of K1? Solution To solve for the work done, first we must determine what is the final kinetic energy of the electron. By concept, we know that K1=(1/2)mv2, K2=(1/2)mv2 But it was mentioned that: V2=( V1 so, K2 in terms of v1 is K2=( )mv2, Substituting the expression for K, results to K2=( K1 Since work done is W=AK=K Evaluating results to W=( )K1 Click Save and Submit to save and submit. Click Save All Answers to save all answers. Save All Answers Close Window Save and Submit 7:01 AM 10/11/2020 近

College Physics
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ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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A moving electron has a Kinetic Energy K1. After a net amount of work is done on it, the electron is moving one-quarter as fast in the opposite direction. What is the work done W in terms of K1?

Solution

To solve for the work done, first we must determine what is the final kinetic energy of the electron.

By concept, we know that

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Take Test: Q2 Culminating PeTa - x
O Messenger
L PHYS1 - Google Drive
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* Question Completion Status:
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A moving electron has a Kinetic Energy K1. After a net amount of work is done on it, the electron is moving one-quarter as fast in the
opposite direction. What is the work done W in terms of K1?
Solution
To solve for the work done, first we must determine what is the final kinetic energy of the electron.
By concept, we know that
K1=(1/2)mv2,
K2=(1/2)mv2
But it was mentioned that:
V2=(
V1
so, K2 in terms of v1 is
K2=(
)mv2,
Substituting the expression for K, results to
K2=(
K1
Since work done is
W=AK=K
Evaluating results to
W=(
)K1
Click Save and Submit to save and submit. Click Save All Answers to save all answers.
Save All Answers
Close Window
Save and Submit
7:01 AM
10/11/2020
近
Transcribed Image Text:A Content Take Test: Q2 Culminating PeTa - x O Messenger L PHYS1 - Google Drive + A ust.blackboard.com/webapps/assessment/take/launch.jsp?course_assessment_id=_255397_1&course_id=_122252_1&content_id= 4246228_1&step=null * Question Completion Status: 1 2 3 4 5 6 A moving electron has a Kinetic Energy K1. After a net amount of work is done on it, the electron is moving one-quarter as fast in the opposite direction. What is the work done W in terms of K1? Solution To solve for the work done, first we must determine what is the final kinetic energy of the electron. By concept, we know that K1=(1/2)mv2, K2=(1/2)mv2 But it was mentioned that: V2=( V1 so, K2 in terms of v1 is K2=( )mv2, Substituting the expression for K, results to K2=( K1 Since work done is W=AK=K Evaluating results to W=( )K1 Click Save and Submit to save and submit. Click Save All Answers to save all answers. Save All Answers Close Window Save and Submit 7:01 AM 10/11/2020 近
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