A variable force of form F(x) = -kx i does work moving from (5.713x10^0) metres to (2.45x10^0) metres. If the constant is k = (1.343x10^2) N/m, calculate the work done by the force in Joules to 2 sf.
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- A spring with a spring constant of (4.4907x10^4) N/m is stretched from an initial extension of (8.00x10^-2) m to a final extension of (2.229x10^-1) m. Calculate the work that must be done by the external force. Give your answer to 2 s.f.the mass of the object is m=0.2kg the spring is compressed at a distance of X=4cm when the mass is released it slides up to the height of 10cm. and then it turns around and slides back down. find the spring constant, K of the spring? WwwM A note: that the equation for spring potential energy is (1/2*k*x2). and gravitational potential energy is m*g*h. also, the conservation of mechanical energy is MEi=MEf.A spring has a natural length of 28 cm. Suppose a 26 N force is required to keep it stretched to a length of 38 cm. (a) What is the exact value of the spring constant (in N/m)? k = N/m (b) How much work W (in J) is required to stretch, it from 28 cm to 33 cm? (Round your answer to two decimal places.) W =
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