**Problem Description:** A 55.0 kg lead ball is dropped from the Leaning Tower of Pisa. The tower is 55.0 m high. **Question:** How far does the ball fall in the first 2.00 seconds of its flight? **Answer Box:** \[ \_\_\_\_\_\_ \text{ m} \] --- **Explanation for Educators:** To solve this problem, use the equation for distance fallen under gravity without initial velocity: \[ d = \frac{1}{2} g t^2 \] where: - \( d \) is the distance fallen, - \( g \) is the acceleration due to gravity (\(9.8 \, \text{m/s}^2\)), - \( t \) is the time in seconds. By substituting \( t = 2.00 \) s into the equation, the distance can be calculated as follows: \[ d = \frac{1}{2} \times 9.8 \times (2.00)^2 \] \[ d = \frac{1}{2} \times 9.8 \times 4 \] \[ d = 19.6 \, \text{m} \] Thus, the ball falls 19.6 meters in the first 2.00 seconds of its flight.

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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**Problem Description:**

A 55.0 kg lead ball is dropped from the Leaning Tower of Pisa. The tower is 55.0 m high.

**Question:**

How far does the ball fall in the first 2.00 seconds of its flight?

**Answer Box:**

\[ \_\_\_\_\_\_ \text{ m} \]

---

**Explanation for Educators:**

To solve this problem, use the equation for distance fallen under gravity without initial velocity:

\[ d = \frac{1}{2} g t^2 \]

where:
- \( d \) is the distance fallen,
- \( g \) is the acceleration due to gravity (\(9.8 \, \text{m/s}^2\)),
- \( t \) is the time in seconds.

By substituting \( t = 2.00 \) s into the equation, the distance can be calculated as follows:

\[ d = \frac{1}{2} \times 9.8 \times (2.00)^2 \]

\[ d = \frac{1}{2} \times 9.8 \times 4 \]

\[ d = 19.6 \, \text{m} \]

Thus, the ball falls 19.6 meters in the first 2.00 seconds of its flight.
Transcribed Image Text:**Problem Description:** A 55.0 kg lead ball is dropped from the Leaning Tower of Pisa. The tower is 55.0 m high. **Question:** How far does the ball fall in the first 2.00 seconds of its flight? **Answer Box:** \[ \_\_\_\_\_\_ \text{ m} \] --- **Explanation for Educators:** To solve this problem, use the equation for distance fallen under gravity without initial velocity: \[ d = \frac{1}{2} g t^2 \] where: - \( d \) is the distance fallen, - \( g \) is the acceleration due to gravity (\(9.8 \, \text{m/s}^2\)), - \( t \) is the time in seconds. By substituting \( t = 2.00 \) s into the equation, the distance can be calculated as follows: \[ d = \frac{1}{2} \times 9.8 \times (2.00)^2 \] \[ d = \frac{1}{2} \times 9.8 \times 4 \] \[ d = 19.6 \, \text{m} \] Thus, the ball falls 19.6 meters in the first 2.00 seconds of its flight.
Expert Solution
Step 1

According to question---

Given values---

  • mass m = 55 kg.
  • initial speed = 0 m/s .
  • tower height = 55 m.
  • time = 2 sec.

We have to find--

  • How far does the ball fall in the first 2.00 s of its flight?
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