Questions in the attachments Diagram 2R2R3R1SR4R5 Refer to diagram 2,PART A.Suppose R, = 87.1 Q, R, = 29.2 Q, R3 = 50.2 0, R4 = 22.9 Q, R5 = 89 Qand V = 918 V. If the switch is open, find the current through R4, inAmperes.PART B.Suppose R, = 1.44 Q, R, = 8.5 N, R3 = 3.02 Q, R4 = 1.82 Q, R5 = 6.02 Q%3Dand V = 544 V. If the switch is closed, find the current through R, , inAmperes.

(A) Given that the switch is open. R3 and the parallel connected R4 and R5 are in series, the…

Answered: Diagram 2 R2 R3 R1 S R4 R5 Refer to…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Questions in the attachments

Refer to diagram 2,
PART A.
Suppose R, = 87.1 Q, R, = 29.2 Q, R3 = 50.2 0, R4 = 22.9 Q, R5 = 89 Q
and V = 918 V. If the switch is open, find the current through R4, in
Amperes.
PART B.
Suppose R, = 1.44 Q, R, = 8.5 N, R3 = 3.02 Q, R4 = 1.82 Q, R5 = 6.02 Q
%3D
and V = 544 V. If the switch is closed, find the current through R, , in
Amperes.

Expert Solution

Step 1

(A)

Given that the switch is open. R₃ and the parallel connected R₄and R₅ are in series, the combination of R₃, R₄ and R₅ is parallel with R₁. The combination of R₁, R₃, R₄ is connected in series with R₂.

Thus, the equivalent resistance of the circuit will be;

$R_{eq} = R_{2} + \frac{R_{1} (R_{3} + R_{4})}{R_{1} + (R_{3} + R_{4})} R_{eq} = (29.2) + \frac{(87.1) (50.2 + 22.9)}{(87.1) + (50.2 Ω + 22.9)} Ω R_{eq} = 68.94 Ω$

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