Physical Science: Height of a Thrown Object. A rock is thrown directly upward with an initial velocity of 50 ft/sec from an initial height of 10 ft.The velocity of this rock is modeled by the function v(t)= -32t +50, where t is in seconds, v is in feet per second, and t=0 represents the moment the rock is released. a) Determine a distance function has a function of t(in this case, "distance" is the same as"height". Be sure to consider the fact that at t=0,the rock is 10ft above the ground. b)Determine the height and the velocity of the rock after 3 sec.

Algebra and Trigonometry (6th Edition)
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ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
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Physical Science: Height of a Thrown Object.
A rock is thrown directly upward with an initial velocity of 50 ft/sec from an initial height of 10 ft.The velocity of this rock is
modeled by the function v(t)= -32t +50, where t is in seconds, v is in feet per second, and t=0 represents the moment the
rock is released.
a) Determine a distance function has a function of t(in this case, "distance" is the same as"height".Be sure to consider the fact
that at t=0,the rock is 10ft above the ground.
b)Determine the height and the velocity of the rock after 3 sec.
Transcribed Image Text:Physical Science: Height of a Thrown Object. A rock is thrown directly upward with an initial velocity of 50 ft/sec from an initial height of 10 ft.The velocity of this rock is modeled by the function v(t)= -32t +50, where t is in seconds, v is in feet per second, and t=0 represents the moment the rock is released. a) Determine a distance function has a function of t(in this case, "distance" is the same as"height".Be sure to consider the fact that at t=0,the rock is 10ft above the ground. b)Determine the height and the velocity of the rock after 3 sec.
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