A potato is launched vertically upward with an initial velocity of 170 feet per second from a potato gun at the top of an 66-foot-tall building. The distance in feet that the potato travels from the ground after t seconds is given by s(t) 16+2 + 170t + 66. a) Find the velocity of the potato after 2.2 seconds and 7 seconds. At t = 2.2 seconds, v = At t = 7 seconds, v = feet per second. feet per second. b) Find the speed of the potato at 2.2 second and 7 seconds. At t = 2.2 seconds, the speed of the potato is At t = 7 seconds, the speed of the potato is c) Determine when the potato reaches its maximum height. t seconds Determine how long the potato is in the air. seconds. d) Find the acceleration of the potato at 2.2 seconds and 7 seconds. At t = 2.2 seconds, a = At t = 7 seconds, a = feet per second. Determine the velocity of the potato upon hitting the ground. feet per second. feet per second. feet per second per second. feet per second per second.
A potato is launched vertically upward with an initial velocity of 170 feet per second from a potato gun at the top of an 66-foot-tall building. The distance in feet that the potato travels from the ground after t seconds is given by s(t) 16+2 + 170t + 66. a) Find the velocity of the potato after 2.2 seconds and 7 seconds. At t = 2.2 seconds, v = At t = 7 seconds, v = feet per second. feet per second. b) Find the speed of the potato at 2.2 second and 7 seconds. At t = 2.2 seconds, the speed of the potato is At t = 7 seconds, the speed of the potato is c) Determine when the potato reaches its maximum height. t seconds Determine how long the potato is in the air. seconds. d) Find the acceleration of the potato at 2.2 seconds and 7 seconds. At t = 2.2 seconds, a = At t = 7 seconds, a = feet per second. Determine the velocity of the potato upon hitting the ground. feet per second. feet per second. feet per second per second. feet per second per second.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question
Expert Solution
Step 1
Solution:
(a) s = -16t2 + 170t + 66
Velocity is given by,
v = ds/dt = 170 - 32t
So, at t = 2.2 seconds, velocity is (170 - 32x2.2) = 99.6 ft/sec upwards. [Ans]
At t = 7 seconds, velocity is (170 - 32x7) = -54 ft/sec, i.e., 54 ft/sec downwards. [Ans]
(b) distance travelled in t = 2.2 seconds is (-16x2.22 + 170x2.2 + 66) = 362.56 ft
So, speed at t = 2.2 seconds is 362.56/2.2 = 164.8 ft/sec. [Ans]
distance travelled in t = 7 seconds is (-16x72 + 170x7 + 66) = 472 ft.
So, speed at t = 7 seconds is 472/7 ≈67.43 ft/sec. [Ans]
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