#4 # PHYS 2263 (Physics II) - Homework 4---### 1. A ray of light is shone through the interface between two media. At a depth of 5 meters below the interface, the light ray has traveled 2 meters horizontally. If it had not been refracted, it would have traveled 3 meters horizontally at this depth. Find the ratio \(\frac{n_2}{n_1}\). Where \(n_1\) is the index of refraction of the material above the interface and \(n_2\) is the index of refraction of the material below the interface.---### 2.Draw a raytrace diagram of an object and its reflected image in a convex mirror.---### 3.Using the same setup as in problem 1, find the critical angle for total internal reflection between medium 2 and medium 1.---### 4.An object is placed twice the focal distance from a concave mirror.(a) Find the magnification of the object. (b) Is the image upright or inverted? (c) Same as in part (a), except now the object is placed at half the focal distance from the mirror.---### 5.If a lens has radii of curvature \(R_1 = 1.1\) meters and \(R_2 = 1.2\) meters and a focal length of 10 centimeters, what is the index of refraction of the lens?---### Diagrams/Graphs:There are no diagrams or graphs provided in this text. However, problem 2 requests the creation of a raytrace diagram, which should illustrate the path of rays from an object as they reflect in a convex mirror.

Solution 1: Let d and d' be the real and apparent depth of the image and n1 and n2 be the refractive…

PHYS 2263 (Physics II) Homework 4 1. A ray of light is shone through the interface between two media. At a depth of 5 meters below the interface, the light ray has travelled 2 meters horizonally. If it had not been refracted, it would have travelled 3 meters horizonally at this depth. Find the ratio . Where ng is the index of refraction of the material above the interface and nz is the index of refraction of the material below the interface.

PHYS 2263 (Physics II) Homework 4 1. A ray of light is shone through the interface between two media. At a depth of 5 meters below the interface, the light ray has travelled 2 meters horizonally. If it had not been refracted, it would have travelled 3 meters horizonally at this depth. Find the ratio . Where ng is the index of refraction of the material above the interface and nz is the index of refraction of the material below the interface.