Phthalonitrile (C3H,N2) is produced by the ammoxidation of o-xylene (C3H10) according to the following reaction: C3H10(1) + O2(g) + NH3(g) → C3H,N2(s) + H¿O(1) How many moles of water would be produced by the complete ammoxidation of 65.5 grams of o- xylene?
Phthalonitrile (C3H,N2) is produced by the ammoxidation of o-xylene (C3H10) according to the following reaction: C3H10(1) + O2(g) + NH3(g) → C3H,N2(s) + H¿O(1) How many moles of water would be produced by the complete ammoxidation of 65.5 grams of o- xylene?
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Phthalonitrile (C3H&N2) is produced
by the ammoxidation of o-xylene
(C3H10) according to the following
reaction:
C3H10(1) + O2(g) + NH3(g) →
C3H¾N2(s) + H2O(1)
How many moles of water would be
produced by the complete
ammoxidation of 65.5 grams of o-
xylene?
|mol
1
2
3
4
C
7
9.
+/-
x 10 0
LO
00](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa28a1da2-fd36-43c5-ae8b-5e2578deb662%2F2cbadea0-1553-47ad-ac7f-70000dd59496%2F0r2v4v9_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Question 1 of 20
Submit
Phthalonitrile (C3H&N2) is produced
by the ammoxidation of o-xylene
(C3H10) according to the following
reaction:
C3H10(1) + O2(g) + NH3(g) →
C3H¾N2(s) + H2O(1)
How many moles of water would be
produced by the complete
ammoxidation of 65.5 grams of o-
xylene?
|mol
1
2
3
4
C
7
9.
+/-
x 10 0
LO
00
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