Question 1 of 20SubmitPhthalonitrile (C3H&N2) is producedby the ammoxidation of o-xylene(C3H10) according to the followingreaction:C3H10(1) + O2(g) + NH3(g) →C3H¾N2(s) + H2O(1)How many moles of water would beproduced by the completeammoxidation of 65.5 grams of o-xylene?|mol1234C79.+/-x 10 0LO00

Stoichiometric relation is used to find the relation between the quantity of reactant and product

Phthalonitrile (C3H,N2) is produced by the ammoxidation of o-xylene (C3H10) according to the following reaction: C3H10(1) + O2(g) + NH3(g) → C3H,N2(s) + H¿O(1) How many moles of water would be produced by the complete ammoxidation of 65.5 grams of o- xylene?

Phthalonitrile (C3H,N2) is produced by the ammoxidation of o-xylene (C3H10) according to the following reaction: C3H10(1) + O2(g) + NH3(g) → C3H,N2(s) + H¿O(1) How many moles of water would be produced by the complete ammoxidation of 65.5 grams of o- xylene?

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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