PHP Im not sure what might be the problem here, the code is not working, the error says :: Parse error: syntax error, unexpected variable "$convert". Thank you! ... dollar = $dollar; $this -> peso = 50.45 * ($this -> $dollar); } // DESTRUCTOR function __destruct() { echo $this -> dollar. "Dollar is equivalent to " . $this -> peso . " peso \n"; } // OBJECT const $convert = new Convert(2); } ?>
PHP Im not sure what might be the problem here, the code is not working, the error says :: Parse error: syntax error, unexpected variable "$convert". Thank you! ... dollar = $dollar; $this -> peso = 50.45 * ($this -> $dollar); } // DESTRUCTOR function __destruct() { echo $this -> dollar. "Dollar is equivalent to " . $this -> peso . " peso \n"; } // OBJECT const $convert = new Convert(2); } ?>
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Im not sure what might be the problem here, the code is not working, the error says :: Parse error: syntax error, unexpected variable "$convert". Thank you!
Im not sure what might be the problem here, the code is not working, the error says :: Parse error: syntax error, unexpected variable "$convert". Thank you!
...
<?php
class Convert // CLASS
{
// VARIABLES
Public $dollar;
Public $peso;
// CONSTRUCTOR
function __construct($dollar)
{
$this -> dollar = $dollar;
$this -> peso = 50.45 * ($this -> $dollar);
}
// DESTRUCTOR
function __destruct()
{
echo $this -> dollar. "Dollar is equivalent to " . $this -> peso . " peso \n";
}
// OBJECT
const $convert = new Convert(2);
}
?>
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