Phosphorus in urine can be done by treating with molybdenum (VI) and then reducing the phosphomolybdate with aminonaphthol sulfonic acid to give the characteristic blue color. The wavelength of maximum absorption was at 690 nm. A patient excreted 1270 mL urine in 24 h, and the pH of the urine was 6.5. A 1.00-ml aliquot of the urine was treated with molybdate reagent and aminonaphthol sulfonic acid and was diluted to a volume of 50.0 mL. A series of phosphate standards was similarly treated. The absorbance of the solutions at 690 nm, measured against a blank, were as follows: alution
Phosphorus in urine can be done by treating with molybdenum (VI) and then reducing the phosphomolybdate with aminonaphthol sulfonic acid to give the characteristic blue color. The wavelength of maximum absorption was at 690 nm. A patient excreted 1270 mL urine in 24 h, and the pH of the urine was 6.5. A 1.00-ml aliquot of the urine was treated with molybdate reagent and aminonaphthol sulfonic acid and was diluted to a volume of 50.0 mL. A series of phosphate standards was similarly treated. The absorbance of the solutions at 690 nm, measured against a blank, were as follows: alution
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
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![Phosphorus in urine can be done by treating with molybdenum (VI) and then reducing the
phosphomolybdate with aminonaphthol sulfonic acid to give the characteristic blue color. The
wavelength of maximum absorption was at 690 nm. A patient excreted 1270 ml urine in 24 h, and the
pH of the urine was 6.5. A 1.00-ml aliquot of the urine was treated with molybdate reagent and
aminonaphthol sulfonic acid and was diluted to a volume of 50.0 mL. A series of phosphate standards
was similarly treated. The absorbance of the solutions at 690 nm, measured against a blank, were as
follows:
Solution
Absorbance
Blank
0.005
1.0 ppm P
0.205
2.0 ppm P
0.410
3.0 ppm P
4.0 ppm P
0.615
0.820
urine sample
0.625
a. Correct the absorbances of the standards and sample through subtracting the absorbance of the
blank. Plot corrected absorbance as a function of the concentration of P standard. Create a
calibration curve using and determine the slope and y-intercept. And Calculate the
concentration of phosphorous in the analyzed sample.
b. Calculate the number of grams of phosphorus excreted per day by the patient.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3c1b8d35-43f1-4bd8-9cc7-7716fa207db0%2F5e8e4864-65b9-4d10-b2d9-6d619e241ab9%2Fwylgoxm_processed.png&w=3840&q=75)
Transcribed Image Text:Phosphorus in urine can be done by treating with molybdenum (VI) and then reducing the
phosphomolybdate with aminonaphthol sulfonic acid to give the characteristic blue color. The
wavelength of maximum absorption was at 690 nm. A patient excreted 1270 ml urine in 24 h, and the
pH of the urine was 6.5. A 1.00-ml aliquot of the urine was treated with molybdate reagent and
aminonaphthol sulfonic acid and was diluted to a volume of 50.0 mL. A series of phosphate standards
was similarly treated. The absorbance of the solutions at 690 nm, measured against a blank, were as
follows:
Solution
Absorbance
Blank
0.005
1.0 ppm P
0.205
2.0 ppm P
0.410
3.0 ppm P
4.0 ppm P
0.615
0.820
urine sample
0.625
a. Correct the absorbances of the standards and sample through subtracting the absorbance of the
blank. Plot corrected absorbance as a function of the concentration of P standard. Create a
calibration curve using and determine the slope and y-intercept. And Calculate the
concentration of phosphorous in the analyzed sample.
b. Calculate the number of grams of phosphorus excreted per day by the patient.
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