Phosphate can be removed from drinking water supplies by treating the water with Ca(OH)2: 5Ca(OH)2(aq) +3PO4(aq) Cas(PO4)3(s) + 90H(aq) How much Ca(OH)2 is required to remove 90.0% of the PO43- from 6.10x106 L of drinking water containing 25.0 mg/L of PO4³-? g

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