PH115_Lab_E_FILE... Q 2 more mobile that the ions, results in a charge density distribution that looks like an avalanche (the so-called Townsend avalanche, see Fig. 6 lower panel). This implies that during the moment of the discharge the flow of electrons towards the anode have greater linear charge density leading to a more luminous terminal connection. 6.1 VDG calculations At this point we need to go through a few back-of-the-envelope calculations pertinent to the VDG; Remember that all the charges on an inductor (like the VDG) reside on its surface, therefore "r" stands for the distance from the VDG's surface. The VDG can store charge up to Q = CV (6) where V is the VDG voltage and C is its capacitance. We have not yet covered in class the term capacitance (discussed in lab 4) however what you need to know for now is that (a) a capacitor is a contraption that "stores" charge and (b) the capacitance is a geometrical property (i.e. depends on the dimensions of the capacitor). In the VDG's case, it is only dependent on its radius in that C = 4re,R (7) where R is the VDG radius. Feel free to think of a bucket storing water as a mechanical analogy. In section 4 we discussed that dry air cannot sustain electric fields higher than -3-106 V-m, Therefore, at its surface, the maximum electric field will also be -3-106 Vm, This implies that a 400 13 PH 115-LABORATORY MANUAL, ELECTRIC FIELDS, UAH PHYSICS 2021-2022 VMAX 4 x 10 kV VDG will have a radius of R = -13 cm since the potential is constant inside EMAX 3x 10 the VDG. You should be able to figure out that this value also reflects the maximum spark length that this 400 kV VDG can generate. In practice, this length is almost always less than the theoretical since humidity does not allow a maximum electric field built-up (Can you think why that is and what factors contribute to the humidity around the VDG, especially in a room full of students?). Now it is also important to know how much charge can the VDG store. If we do not allow the VDG to discharge (no charge collector in the vicinity) then the maximum charge it can hold will be QMAX = CVMAX = 4xe,RV = 4xc,R²EMAX This is an interesting relationship and you should easily glean that this is the Gauss' law! Putting in the numbers we get QMAX = (4)(3.14)(8.85 x 10-12)(0.13) (3 x 10") = 5.6µC Is this dangerous for handling? Well, apparently no, but let's see why that is the case; The maximum energy stored in the VDG is given by UMAX =OMAX VMAX = 1.2Joules • Previous Next 16 Dashboard Calendar To Do Notifications Inbox

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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11:07 1
l 5G I
PH115_Lab_E_FILE...
more mobile that the ions, results in a charge density distribution that looks like an avalanche (the
so-called Townsend avalanche, see Fig. 6 lower panel). This implies that during the moment of the
discharge the flow of electrons towards the anode have greater linear charge density leading to a more
luminous terminal connection.
6.1 VDG calculations
At this point we need to go through a few back-of-the-envelope calculations pertinent to the VDG;
Remember that all the charges on an inductor (like the VDG) reside on its surface, therefore “r"
stands for the distance from the VDG's surface. The VDG can store charge up to
Q = CV (6)
where V is the VDG voltage and C is its capacitance. We have not yet covered in class the term
capacitance (discussed in lab 4) however what you need to know for now is that (a) a capacitor is a
contraption that "stores" charge and (b) the capacitance is a geometrical property (i.e. depends on
the dimensions of the capacitor). In the VDG's case, it is only dependent on its radius in that
C = 4xe,R (7)
where R is the VDG radius. Feel free to think of a bucket storing water as a mechanical analogy. In
section 4 we discussed that dry air cannot sustain electric fields higher than -3-106 V-m-!.
Therefore, at its surface, the maximum electric field will also be -3-106 Vm1. This implies that a 400
13
PH 115-LABORATORY MANUAL, ELECTRIC FIELDS, UAH PHYSICS 2021-2022
kV VDG will have a radius of R =
EMAX
VMAX 4x 105
3x 10
=-13 cm since the potential is constant inside
the VDG. You should be able to figure out that this value also reflects the maximum spark length that
this 400 kV VDG can generate. In practice, this length is almost always less than the theoretical since
humidity does not allow a maximum electric field built-up (Can you think why that is and what
factors contribute to the humidity around the VDG, especially in a room full of students?). Now it is also
important to know how much charge can the VDG store. If we do not allow the VDG to discharge (no
charge collector in the vicinity) then the maximum charge it can hold will be
QMAX = CVMAX = 4x€,RV = 4x€,R²EMAX-
This is an interesting relationship and you should easily glean that this is the Gauss' law! Putting in
the numbers we get
QUAY = (4)(3.14)(8.85 x 10-12(0.13)(3 x 10°) = 5.6uC
Is this dangerous for handling? Well, apparently no, but let's see why that is the case; The maximum
energy stored
the VDG is given by
UMAX =QMAXVMAX = 1.2Joules
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Transcribed Image Text:11:07 1 l 5G I PH115_Lab_E_FILE... more mobile that the ions, results in a charge density distribution that looks like an avalanche (the so-called Townsend avalanche, see Fig. 6 lower panel). This implies that during the moment of the discharge the flow of electrons towards the anode have greater linear charge density leading to a more luminous terminal connection. 6.1 VDG calculations At this point we need to go through a few back-of-the-envelope calculations pertinent to the VDG; Remember that all the charges on an inductor (like the VDG) reside on its surface, therefore “r" stands for the distance from the VDG's surface. The VDG can store charge up to Q = CV (6) where V is the VDG voltage and C is its capacitance. We have not yet covered in class the term capacitance (discussed in lab 4) however what you need to know for now is that (a) a capacitor is a contraption that "stores" charge and (b) the capacitance is a geometrical property (i.e. depends on the dimensions of the capacitor). In the VDG's case, it is only dependent on its radius in that C = 4xe,R (7) where R is the VDG radius. Feel free to think of a bucket storing water as a mechanical analogy. In section 4 we discussed that dry air cannot sustain electric fields higher than -3-106 V-m-!. Therefore, at its surface, the maximum electric field will also be -3-106 Vm1. This implies that a 400 13 PH 115-LABORATORY MANUAL, ELECTRIC FIELDS, UAH PHYSICS 2021-2022 kV VDG will have a radius of R = EMAX VMAX 4x 105 3x 10 =-13 cm since the potential is constant inside the VDG. You should be able to figure out that this value also reflects the maximum spark length that this 400 kV VDG can generate. In practice, this length is almost always less than the theoretical since humidity does not allow a maximum electric field built-up (Can you think why that is and what factors contribute to the humidity around the VDG, especially in a room full of students?). Now it is also important to know how much charge can the VDG store. If we do not allow the VDG to discharge (no charge collector in the vicinity) then the maximum charge it can hold will be QMAX = CVMAX = 4x€,RV = 4x€,R²EMAX- This is an interesting relationship and you should easily glean that this is the Gauss' law! Putting in the numbers we get QUAY = (4)(3.14)(8.85 x 10-12(0.13)(3 x 10°) = 5.6uC Is this dangerous for handling? Well, apparently no, but let's see why that is the case; The maximum energy stored the VDG is given by UMAX =QMAXVMAX = 1.2Joules « Previous Next 16 Dashboard Calendar To Do Notifications Inbox
8otng
[Qs-Lab/Home ·**]
Derive an algebraic expression for the charge delivered per unit time as a function of the VDG belt
width, the pulley radius the revolutions per minute and belt's speed. Caution: If you simply copy a
solution from the Internet, this question will get a zero i.e. an explanation that goes with the derivation is
necessary.
Transcribed Image Text:8otng [Qs-Lab/Home ·**] Derive an algebraic expression for the charge delivered per unit time as a function of the VDG belt width, the pulley radius the revolutions per minute and belt's speed. Caution: If you simply copy a solution from the Internet, this question will get a zero i.e. an explanation that goes with the derivation is necessary.
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