Pew research reported in 2013 that 15% of American adults do not use the internet or e-mail. They report a margin oferror of 2.3 percentage points. The meaning of that margin of error isOIf they repeatedly sampled from the population, and constructed a confidence interval for each estimate, about2.3% of those intervals would capture the proportion of American adults who don't use the internet or e-mail.OThey are pretty sure that the poll result differs from the actual percentage of American adults who don't use theinternet or e-mail by 2.3% or less.O There is a 2.3% probability that their estimate is incorrect.OThey are 2.3% confident that their confidence interval captures the true proportion of American adults that don'tuse the internet or e-mail.

This question asks about the meaning of a margin of error reported by Pew Research in 2013 for a…

Answered: Pew research reported in 2013 that 15%…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Several years ago, 46% of parents who had children in grades K-12 were satisfied with the quality of education the students receive. A recent poll asked 1,135 parents who have children in grades K-12 if they were satisfied with the quality of education the students receive. Of the 1,135 surveyed, 474 indicated that they were satisfied. Construct a 90% confidence interval to assess whether this represents evidence that parents' attitudes toward the quality of education have changed. What are the null and alternative hypotheses? Ho: P versus H₁: p (Round to two decimal places as needed.) (…)
Several years ago, 44% of parents who had children in grades K-12 were satisfied with the quality of education the students receive. A recent poll asked 1,075 parents who have children in grades K-12 if they were satisfied with the quality of education the students receive. Of the 1,075 surveyed, 479 indicated that they were satisfied. Construct a 95% confidence interval to assess whether this represents evidence that parents' attitudes toward the quality of education have changed. What are the null and alternative hypotheses? Ho: p = 0.44 versus H,: p 0.44 (Round to two decimal places as needed.) Use technology to find the 95% confidence interval. The lower is The upper bound is (Round to two decimal places as needed.)
The Pew Internet and American Life Project (A-13) reported in 2003 that 18 percent of Internet users have used it to search for information regarding experimental treatments or medicines. The sample consisted of 1220 adult Internet users, and information was collected from telephone interviews. We wish to construct a 95 percent confidence interval for the proportion of Internet users in the sampled population who have searched for information on experimental treatments or medicines. Plus Interpretation
Suppose you calculate a 99% confidence interval of 14.71 to 21.64. Determine the margin of error.
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A sports news station wanted to know whether people who live in the North or the South are bigger sports fans. For its study, 121 randomly selected Southerners were surveyed and found to watch a mean of 4.6 hours of sports per week. In the North, 176 randomly selected people were surveyed and found to watch a mean of 3.2 hours of sports per week. Find a 90% confidence interval for the true difference between the mean numbers of hours of sports watched per week for the two regions if the South has a population standard deviation of 1.6 hours per week and the North has a population standard deviation of 1.4 hours per week. Let Population 1 be people who live in the South and Population 2 be people who live in the North. Round the endpoints of the interval to one decimal place, if necessary. Lower endpoint: Upper endpoint:
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In a recent survey of 1264 US adults, 26.6% said they had seen a ghost. What is the LOWER endpoint of a 98% confidence interval for the population proportion? What is the UPPER endpoint of a 98% confidence interval for the population proportion? Answers should be decimals (not percentages).

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