Peter has $30,000 to invest in a mutual fund whose annual returns are normally distributed with a mean of 5.75% and standarddeviation of 4.97%.a. Use Excel's Analysis ToolPak, with a seed of 1, to simulate 5,000 trials to estimate the mean balance after one year. (RoundIntermediate calculations to at least 4 decimal places and your final answer to 2 decimal places.)Average balance after one yearb. What is the probability of a balance of $33,000 or more? (Round intermediate calculations to at least 4 decimal places and showyour final answer as a percentage point with 2 decimal places.)Probability of having a bailance of $33,000 or morec. Compared to another investment option at a fixed annual return of 3% per year, what is the probability of getting at least the samebalance from the mutual fund after one year? (Round intermediate calculations to at least 4 decimal places and show your finalanswer as a percentage point with 2 decimal places.)

a) In Excel Click Data-Data Analysis-Random Number generator. Then provide the inputs as shown in…

Answered: Peter has $30,000 to invest in a mutual…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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STATISTICS & PROBABILITY Direction: Solve the following problems. Round off your answer to two decimal places. Use the percentage form and include the percentage symbol (%) The length of time needed to do a particular activity is normally distributed with a mean of 2 hours and a standard deviation of 1.25 hours. What is the probability that a randomly selected student will spend 3.5 hours in doing the activity? The monthly food expenditure of a single person is 3000Php on average with a standard deviation of 300Php. Assuming that the monthly food expenditure is normally distributed, what percentage of these expenditures are between 2400Php and 4000Php? Find the area to the right of z = 1.37 Select one: A. 8.53% B. 43.45% C. 31.76% D. 47.88% Find the area between z = 0.46 and z = 2.56 Select one: A. 43.45% B. 31.76% C. 30.15% D. 97.98% Find the area between z = 0 and z = -2.03 Select one: A. 43.45% B. 47.88% C. 8.53% D. 31.76% Find the area to the left…
Over the past six years, a stock had annual returns of 14 percent, -3 percent, 8 percent, 21 percent, -16 percent, and 4 percent, respectively. What is the standard deviation of these returns? 11.27 percent 13.05 percent 13.59 percent 15.08 percent 14.40 percent
Find the probability that more than 68% of the sampled adults drink coffee daily.
Lunch break: In a recent survey of 608 working Americans ages 25-34, the average weekly amount spent on lunch as $45.08 with standard deviation $2.66. The weekly amounts are approximately bell-shaped. Part 1 of 3 (a) Estimate the percentage of amounts that were less than $42.42. Round the answer to one decimal place. Approximately 16 % of the amounts were less than $42.42. Part: 1 / 3 Part 2 of 3 (b) Estimate the percentage of amounts that were greater than $50.40. Round the answer to one decimal place. Approximately % of the amounts were greater than $50.40. X
esc Introduction A chain of restaurants has historically had a mean wait time of 9 minutes for its customers. Recently, the restaurant added several very popular dishes back to their menu. Due to this, the manager suspects the wait time, μ, has increased. He takes a random sample of 44 customers. The mean wait time for the sample is 9.6 minutes. Assume the population standard deviation for the wait times is known to be 3.3 minutes. Can the manager conclude that the mean wait time is now greater than 9 minutes? Perform a hypothesis test, using the 0.05 level of significance. (a) State the null hypothesis Ho and the alternative hypothesis H₁. Ho: O H₁:0 (b) Perform a Z-test and find the p-value. Here is some information to help you with your Z-test. The value of the test statistic is given by Standard Normal Distribution Step 1: Select one-tailed or two-tailed. O One-tailed O Two-tailed Explanation μ Check □<口 X X OSO 020 0=0 x-H √n • The p-value is the area under the curve to the right…
Lunch break: In a recent survey of 654 working Americans ages 25 - 34 , the average weekly amount spent on lunch as $44.36 with standard deviation $2.74 . The weekly amounts are approximately bell-shaped. Part: 0 / 3 0 of 3 Parts Complete Part 1 of 3 (a) Estimate the percentage of amounts that were between $44.36 and $49.84 . Round the answer to one decimal place.
Q7
A stock has an annual expected return of 15% and a standard deviation of 50%. An investor in this stock can expect to lose 10% of their investment or more about once every _____ year(s).a. 5 b. 3 c. 4 d. 2 e. 1. Need typed answer only .Please give answer within 45 minutes
ents this quarter: The Environmental Protection Agency (EPA) fuel economy estimates for automobile models tested recently predicted a mean of 25.8 miles per gallon, with a standard deviation of 5.2 miles per gallon. Assume that a Normal model applies. Find the probability that a randomly selected automobile will average: 1. Less than 21 miles per gallon. 2. More than 15 miles per gallon. 3. Between 24 and 30 miles per gallon. ular paper, making sure to number each problem so I know what work goes with which problem. e sure to complete and sign the academic honesty statement for each assignment you complete this quarter. If you a nvas. Make sure to check your f6ler for legibility and completeness before unlnading
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Plzz explain. Ty

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