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Peter called to a an insurance company and was told that there was one customer ahead of him waiting for starting to be served. Suppose that at each moment, the time remaining for the next service does not depend on when the last service has begun, and the mean service time is 5 minutes. Answer Question 14-15 below. Write an integral that gives the probability that Peter will wait more than 9 min. 02/5, e-x/5 dx So x² e-5x dx 25 05e-2/5dx O 5 ]° xe-z/5da Oxe-x/5dx 25 J9

Peter called to a an insurance company and was told that there was one customer ahead of him waiting for starting to be served. Suppose that at each moment, the time remaining for the next service does not depend on when the last service has begun, and the mean service time is 5 minutes. Answer Question 14-15 below. Write an integral that gives the probability that Peter will wait more than 9 min. 02/5, e-x/5 dx So x² e-5x dx 25 05e-2/5dx O 5 ]° xe-z/5da Oxe-x/5dx 25 J9

A First Course in Probability (10th Edition)
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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Peter called to a an insurance company and was told that there was one customer ahead of him waiting for starting to be served. Suppose that at each moment, the time remaining for the next service does not depend on when the last service has begun, and the mean service time is 5 minutes. Answer Question 14-15 below. Write an integral that gives the probability that Peter will wait more than 9 min. 5,⁹ -x/5 e dx 1 Of x² e-5 dx 25 5e-2/5dx 5 xe 27/15 6,00⁰0 -x/5 dx xe -x/5 dx
Transcribed Image Text:Peter called to a an insurance company and was told that there was one customer ahead of him waiting for starting to be served. Suppose that at each moment, the time remaining for the next service does not depend on when the last service has begun, and the mean service time is 5 minutes. Answer Question 14-15 below. Write an integral that gives the probability that Peter will wait more than 9 min. 5,⁹ -x/5 e dx 1 Of x² e-5 dx 25 5e-2/5dx 5 xe 27/15 6,00⁰0 -x/5 dx xe -x/5 dx
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