Peter, a eacher in a college, randomly his class to complete an assigned task, the sample mean completion time is found. Using this x, Peter found that the 95% confidence interval for the true average time in completing the task is (17.278, 28.722) minutes. Peter thinks that this interval is too wide, that means the speed of students doing an in-class exercise has to be improved. Therefore, he thinks a confidence interval of total width 5 minutes will be more desirable. (Hints: width of C.I. = upper limit minus lower limit) (a) Using the same value of x, find the new confidence interval in this case. (b) Find the confidence level for the interval in part (a).
Peter, a eacher in a college, randomly his class to complete an assigned task, the sample mean completion time is found. Using this x, Peter found that the 95% confidence interval for the true average time in completing the task is (17.278, 28.722) minutes. Peter thinks that this interval is too wide, that means the speed of students doing an in-class exercise has to be improved. Therefore, he thinks a confidence interval of total width 5 minutes will be more desirable. (Hints: width of C.I. = upper limit minus lower limit) (a) Using the same value of x, find the new confidence interval in this case. (b) Find the confidence level for the interval in part (a).
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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i found the z value of 0.8563 from standard normal table is (0.22+0.21)/2=0.215. So the p-value is 2x(0.215)=0.43. The confidence level for new interval is 57%. Why the answers is different to 61%.
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