PES 2150 Prelab Questions 1.) Consider a lens with focal length +f. An erect object located outside the focal length from the lens. a.) Draw a ray diagram for this arrangement to locate the image with all principal rays for a lens. Word has simple drawing tools, under the "Insert" Tab → “Shapes" tools. If you draw your diagram by hand it must be neat and drawn with a straight edge such as a ruler. Insert Draw Des O Shapes Lines Pictures Line angles 1 square = 1 cm b.) Based on your ray diagram characterize: the object vertically upright, erect, situated Ieft to the lens. The objeet heignt is Hem and distance is 16em. the image formed 2f of the lens. The image formed is diminisned between and 1s Ane image formed inverted, Size and is the lens The focal length of the 16 cm. Using Formula ē =-- lens is Image Distance - 5.3 cm c.) Analyze this situation mathematically by calculating the image distance, the image height, and the magnification. By using the sign convention, carefully explain how your mathematical answers corroborate your ray diagram. PES 21 50 - PHYSICS LAB ORATORY II Image distance = Units? Image height = Magnification = Units? Units?

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Please find the image distance, image height and magnification. Provide units as well. Thank you
PES 2150 Prelab Questions
1.) Consider a lens with focal length +f. An erect object located outside the focal length
from the lens.
a.) Draw a ray diagram for this arrangement to locate the image
with all principal rays for a lens. Word has simple drawing
tools, under the "Insert" Tab → “Shapes" tools. If you draw
your diagram by hand it must be neat and drawn with a straight
edge such as a ruler.
Insert
Draw
Des
O Shapes
Lines
Pictures
Line angles
1 square = 1 cm
b.) Based on your ray diagram characterize:
the object vertically upright, crect, situated Ieft to the
lens. The objeet height is Hem
and
distance is
16em.
the image
to
2f
of the
lens. The image formed is diminisned
between
and
1s
the image
formed
inverted,
Size
and
is
the lens The focal length of the
16 cm. Using Formula ē =--
lens is
Image Distance = 5.3 cm
c.) Analyze this situation mathematically by calculating the image distance, the image
height, and the magnification. By using the sign convention, carefully explain
how your mathematical answers corroborate your ray diagram.
PES 2150 -
PHYSICS
LABORATORY
Image distance =
Image height =
Magnification =
Units?
Units?
Units?
Transcribed Image Text:PES 2150 Prelab Questions 1.) Consider a lens with focal length +f. An erect object located outside the focal length from the lens. a.) Draw a ray diagram for this arrangement to locate the image with all principal rays for a lens. Word has simple drawing tools, under the "Insert" Tab → “Shapes" tools. If you draw your diagram by hand it must be neat and drawn with a straight edge such as a ruler. Insert Draw Des O Shapes Lines Pictures Line angles 1 square = 1 cm b.) Based on your ray diagram characterize: the object vertically upright, crect, situated Ieft to the lens. The objeet height is Hem and distance is 16em. the image to 2f of the lens. The image formed is diminisned between and 1s the image formed inverted, Size and is the lens The focal length of the 16 cm. Using Formula ē =-- lens is Image Distance = 5.3 cm c.) Analyze this situation mathematically by calculating the image distance, the image height, and the magnification. By using the sign convention, carefully explain how your mathematical answers corroborate your ray diagram. PES 2150 - PHYSICS LABORATORY Image distance = Image height = Magnification = Units? Units? Units?
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