Person(Name, Age, Phone, Extension)Find all names whose Extension starts with 5 followed by any single digit and ends withNote that data type of Extension is CHAR(3)Select one:SELECT Name FROM person where Phone LIKE '%5_7'SELECT Name FROM person where Phone LIKE '5_7'SELECT Name FROM person where Phone LIKE '%5%7'SELECT Name FROM person where Phone LIKE '5%7

we want it to start from 5, have exactly one character in the second place, which is denoted by the…

Person(Name, Age, Phone, Extension) Find all names whose Extension starts with 5 folllowed by any single digit and ends with 7. Note that data type of Extension is CHAR(3) Select one: O SELECT Name FROM person where Phone LIKE %5_7' O SELECT Name FROM person where Phone LIKE '5_7' O SELECT Name FROM person where Phone LIKE "%5%7' O SELECT Name FROM person where Phone LIKE '5%7'

Person(Name, Age, Phone, Extension) Find all names whose Extension starts with 5 folllowed by any single digit and ends with 7. Note that data type of Extension is CHAR(3) Select one: O SELECT Name FROM person where Phone LIKE %5_7' O SELECT Name FROM person where Phone LIKE '5_7' O SELECT Name FROM person where Phone LIKE "%5%7' O SELECT Name FROM person where Phone LIKE '5%7'

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Replace all the 0 (Zero) digits in your ID by 4. Example: If your ID is 382200448 , it becomes 382244448 Take the first 6 digits and substitute them in this expression (( A + B) / C) * ((D-E)/F)-2) according to the following table; [1 mark] Letter Replace by Digit Example Digit A 1st 3 B 2nd 8 C 3rd 2 D 4th 2 E 5th 4 F 6th 4 After substitution your expression ? Draw a rooted tree that represents your expression. [3 marks] What is the prefix form of this expression. [3 marks] What is the value of the prefix expression obtained in step 2 above? [3 marks]
this is the information that has to be hard-coded: # hard-coded calls jim = User(first_name='Jim', last_name='Bob', user_id=1000, last_login='June 12, 1998', password='password123') jim.describe_user() jim.greet_user() joe = User('Joe', 'Bob', 1001, 'July 4, 2001', 'babygirl') joe.greet_user() joe.describe_user()
like that declarecursor c isselect first_name, last_name, department_idfrom employeeswhere to_char(hire_date, 'ddd') > 100; v_fname employees.first_name%type;v_lname employees.last_name%type;v_deptid employees.department_id%type; beginopen c;loopfetch c into v_fname, v_lname, v_deptid;exit when c%notfound;dbms_output.put_line('First Name: '|| v_fname);dbms_output.put_line('Last Name: '|| v_lname);dbms_output.put_line('Department ID: '|| v_deptid);dbms_output.put_line(' ');end loop;close c; end; Display the first name and salary*10000 of all employees who works for department 50. Handle exceptions like Invalid cursor, cursor already open and no data found with oracle pl sql
This kind of code gives me errors i have more info below. My codeDELIMITER //CREATE PROCEDURE GET_INVOICE_DATE (in I_INVOICE_NUM CHAR(5))DECLARE I_CUST_ID CHAR(5),DECLARE I_CUST_NAME VARCHAR(41),DECLARE I_INVOICE_DATE DATE BEGIN SELECT c.CUST_ID, CONCAT(c.FIRST_NAME, ' ', c.LAST_NAME), i.INVOICE_DATE INTO I_CUST_ID, I_CUST_NAME, I_INVOICE_DATE FROM INVOICES i INNER JOIN CUSTOMER c ON i.CUST_ID = c.CUST_ID WHERE i.INVOICE_NUM = I_INVOICE_NUM; END // Delimiter ; Helpfull info Task #6 – same process as Task #5• Procedure name is GET_INVOICE_DATE with I_INVOICE_NUM in parentheses with 5 characters• There should be 3 declare statements for I_CUST_ID CHAR(5); I_CUST_NAME VARCHAR(41); andI_INVOICE_DATE DATE is datatype• SELECT statement should include the CUSTOMER.CUST_ID, CONCAT for first_name andlast_name AS customer_name, invoice_date• INTO the 3 “I” fields in the declare statement• From should include the CUSTOMER and INVOICES tables• Where clause to join CUSTOMER.CUST_ID =…
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For questions below, use the following nested data structure to answer the questions. social_network = {'bb_dawg$': ('Barry Bowden', 18, ['New York City NY', 'Langley VA'], ['Elisa Yang', 'Andrew Yamins', 'James Butler']), 'yo_jimbo2000': ('James Butler', 21, ['Boston MA'], ['Barry Bowden']), 'e_yan2002': ('Elisa Yan', 20, ['College Park MD', 'Clarksburg MD'], ['Andrew Yamins', 'Barry Bowden']), 'bmansford1990': ('Benard Mansford', 31, ['San Jose CA', 'College Park MD'], []), 'derp1234': ('who cares', 99, ['College Park MD'], [])} Q1) Notice that a removed user ('Andrew Yamins') is still contained in the friends list of a few users. Write a few lines of code to remove him from those friends lists in the social network. Q2) Write a short Python function called find_user_lived that takes a string as input along with the social network data structure; the string should be a city and state and the function should…
B questions 21-24, please check my work if it’s correct, thank you
The following is a sample report from a child clinic. It shows the days and treatments for visits to doctors at the clinic. A mother takes her child, sees a doctor and the doctor administers some treatment. There are couple of things you should assume: The mother’s name is unique. a mother won't have more than one child with the same name the doctor's surname is unique a treatment code is unique treatments are specific to doctors, eg 101 is only ever given by Johnson Surname First Name Town Age Child Doctor Date Treatment Smith Jane Coventry 30 Rebecca Johnson 27.3.04 101 Brian Clarence 30.5.04 209 Robert Johnson 10.1.88 101 Brown Beryl Rugby 28 Alan Clarence 30.4.04 214 Sarah Johnson 29.5.04 101 Sarah Clarence 12.1.04 321 Jones Fiona Kenilworth 34 James Clarence 30.4.04 322 Jenny…
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DO NOT COPY FROM OTHER WEBSITES Code with comments and output screenshot is must. PYTHON
Based on the table below, what values would appear in the range D3:F5 when the contents of C3:C5 are autofilled rightward towards column F? 1 2 3 4 5 A Blank # 1 Blank # 2 Blank #3 Blank # 4 Blank # 5 Blank # 6 Blank # 7 Blank # 8 Blank # 9 8 Initial Values C3=C$2*3 C4=$C2*3 C5=$C$2*3 C 1 3 3 3 D 2 Blank # 1 Blank # 4 Blank #7 E 3 Blank # 2 Blank # 5 Blank # 8 4 Blank # 3 Blank # 6 Blank # 9 A/ F A A/ A N A 신 A A/