Homework Help is Here – Start Your Trial Now!
Math
Geometry
%3D DE, AC = DF, and mLA = mLD. %3D Below are AABC and ADEF.We assume that AB: B D %23 A F E Here is a rough outline of a proof that AABC ADEF: %3D 1. We can map AABC using a sequence of rigid transformations so that A' = D, B' and E are on the same ray from D, and C and F are on the same ray from D. [Show drawing.] 2. As a result of these transformations, B' must coincide with E.[Show drawing.] 3. As a result of these transformations, C' must coincide with F.[Show drawing.]

%3D DE, AC = DF, and mLA = mLD. %3D Below are AABC and ADEF.We assume that AB: B D %23 A F E Here is a rough outline of a proof that AABC ADEF: %3D 1. We can map AABC using a sequence of rigid transformations so that A' = D, B' and E are on the same ray from D, and C and F are on the same ray from D. [Show drawing.] 2. As a result of these transformations, B' must coincide with E.[Show drawing.] 3. As a result of these transformations, C' must coincide with F.[Show drawing.]

Elementary Geometry For College Students, 7e
Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
See similar textbooks
icon
Related questions
Topic Video
Question

Attached is the full question. I need to answer what fact can justify step 1? Ty

Below are AABC and ADEF.We assume that AB = DE, AC = DF,and mZA= mZD. A F E Here is a rough outline of a proof that AABC = ADEF: 1. We can mapAABC using a sequence of rigid transformations so that A' = D,B' and E are on the same ray from D, and C" and F are on the same ray from D.[Show drawing.] 2. As a result of these transformations, B' must coincide with E.[Show drawing.]. 3. As a result of these transformations, C' must coincide with F. [Show drawing.] What fact can we use to justify step 1? What fact can we use to justify step 1? Choose 1 answer: AB = DE and segments with the same length are congruent. AC = DF and segments with the same length are congruent. C mZA= mZD and angles with the same measure are congruent.
Transcribed Image Text:Below are AABC and ADEF.We assume that AB = DE, AC = DF,and mZA= mZD. A F E Here is a rough outline of a proof that AABC = ADEF: 1. We can mapAABC using a sequence of rigid transformations so that A' = D,B' and E are on the same ray from D, and C" and F are on the same ray from D.[Show drawing.] 2. As a result of these transformations, B' must coincide with E.[Show drawing.]. 3. As a result of these transformations, C' must coincide with F. [Show drawing.] What fact can we use to justify step 1? What fact can we use to justify step 1? Choose 1 answer: AB = DE and segments with the same length are congruent. AC = DF and segments with the same length are congruent. C mZA= mZD and angles with the same measure are congruent.
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps with 1 images

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer
Knowledge Booster
Research Design Formulation
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, geometry and related others by exploring similar questions and additional content below.
Recommended textbooks for you
Elementary Geometry For College Students, 7e
Elementary Geometry For College Students, 7e
Geometry
ISBN:
9781337614085
Author:
Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:
Cengage,
Elementary Geometry for College Students
Elementary Geometry for College Students
Geometry
ISBN:
9781285195698
Author:
Daniel C. Alexander, Geralyn M. Koeberlein
Publisher:
Cengage Learning
SEE MORE TEXTBOOKS