fprintf('13 = %4.3f mAmps\n', 13*1000); % Voltage Drop Calculation Across each resistor VR1 = R1*11; VR2 = R2* (11-12); VR3 = R3*12; VR4 = R4* (12-13); % Power Dissipation Calculation by Each Resistor PR1 = VR1*11; PR2 = VR2* (11-12); PR3 = VR3*12; PR4 = VR4* (12 - 13); % Display of Voltage Drops and Power Dissipations fprintf(' fprintf('VOLTAGE DROPS \t\t\t POWER DISSIPATION : \n'); fprintf('= ========== ====== =\n'); =======\n'); fprintf('VR1 = %4.2f Volts \t\t PR1 = %4.3f mWatts \n', VR1, PR1*1000); fprintf('VR2 = %4.2f Volts \t\t PR2 = %4.3f mWatts \n', VR2, PR2*1000); fprintf('VR3 = %4.2f Volts \t\t PR3 = %4.3f mWatts \n', VR3, PR3*1000); fprintf('VR4 fprintf('- = %4.2f Volts \t\t PR4 = %4.3f mWatts \n', VR4, PR4*1000); =\n'); % INPUT SECTION % At this point We Enter the Resistor values and Voltage Source Values fprintf('Provide Resistance Values for the Resistors as Requested: \n'); fprintf(' ====\n'); % Ensure valid resistor values (at least 4 resistors) R1x = input_with_validation ('Enter the value for R1 in KOhms: '); R2x = input_with_validation ('Enter the value for R2 in Kohms: '); R3x = input_with_validation ('Enter the value for R3 in Kohms: '); R4x = input_with_validation('Enter the value for R4 in KOhms : '); % Voltage sources fprintf('Provide Voltage values for the Voltage Sources as requested: \n'); fprintf('===➖➖➖➖➖➖➖➖ ======== ==========\n'); =================== E1 = input_with_validation ('Enter the value for E1 in Volts : '); E2 = input_with_validation("Enter the value for E2 in Volts: '); E3 = input_with_validation ('Enter the value for E3 in Volts: '); % Scaling Factor: Multiplication of Resistors by 1000 (1K) each R1 = 1000*R1x; R2 = 1000*R2x; R3 = 1000 R3x; R4 = 1000*R4x; fprintf('VALUES YOU HAVE ENTERED FOR YOUR CIRCUIT: \n'); fprintf('********* *******\n'); fprintf('R1 = %4.2f KOhms\n', R1x);| fprintf('R2 = %4.2f KOhms\n', R2x); fprintf('R3 = %4.2f KOhms\n', R3x); fprintf('R4 = %4.2f KOhms\n', R4x); fprintf('E1 = %4.2f Volts\n', E1); fprintf('E2 = %4.2f Volts \n', E2); fprintf('E3 = %4.2f Volts \n', E3); % Matrix Creation Step for a system with 4 resistors and 3 voltage sources R11 = R1 + R2; % Combine R1 and R2 resistors R22 R2 + R3 + R4; % Combine R2, R3, and R4 resistors % Update the A matrix to accommodate the 4 resistors system A = [R11 -R2 0; -R2 R22 -R3; 0-R3 R4]; b = [(E1 E2) E2 E3]'; % Vector for the 3 voltage sources - % COMPUTATION SECTION % Current Calculation (using the system of equations) I = A\b; % Solve using more numerically stable approach % Reassignment of Currents to a more meaningful form I1 = I(1); 12 = I(2); 13 = I(3); % OUTPUT SECTION fprintf(" ****** fprintf('******** OUTPUT RESULTS ****\n'); *******\n'); fprintf('******** CURRENTS: *********\n'); fprintf('11 = %4.34 mAmps\n', 11*1000); fprintf('12 = %4.3f mAmps\n', 12*1000);