Percent Composition Practice #1 Find the percent compositions of all of the elements in the following compounds: EXAMPLE 1) CuBr2 Molar Mass = 1(Cu)+2(Br) 1(63.546) + 2(79.904) =223.354 g/mol %Cu = (63.546÷223.354) x 100 = 28.45% %Br = (159.808÷223.354) x 100 = 71.55% 1) Mg(NO3)2 2) (NH4)3PO4 Cu: 28.45% Br: 71.55% Mg: N: O: N: H:
Percent Composition Practice #1 Find the percent compositions of all of the elements in the following compounds: EXAMPLE 1) CuBr2 Molar Mass = 1(Cu)+2(Br) 1(63.546) + 2(79.904) =223.354 g/mol %Cu = (63.546÷223.354) x 100 = 28.45% %Br = (159.808÷223.354) x 100 = 71.55% 1) Mg(NO3)2 2) (NH4)3PO4 Cu: 28.45% Br: 71.55% Mg: N: O: N: H:
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:7:56 PM Mon Jan 9
Percent_Composition_Practice_1
Jan 9, 2023 at 3:44 PM
T
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2) (NH4)3PO4
Percent Composition Practice #1
Find the percent compositions of all of the elements in the following compounds:
EXAMPLE 1) CuBr2
Molar Mass = 1(Cu)+2(Br)
1(63.546) + 2(79.904) =223.354 g/mol
%Cu = (63.546÷223.354) x 100 = 28.45%
%Br = (159.808÷223.354) x 100 = 71.55%
1) Mg(NO3)2
어
Cu: 28.45%
Br: 71.55%
Mg:
N:
O:
N:
H:
40%
+ :
1
/
3
<
←
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