a) A 4.00L tank at 25.0° C is filled with 4.0 g of nitrogen monoxide (NO) and 8.3 g of sulfur hexafluoride gas (SF6). What is the mole fraction of sulfur hexafluoride? A) 0.17 B) 0.21 C) 0.48 D) 0.67 E) 0.30 F) 0.43 b) What is the ratio between the rates of effusion of sulfur hexafluoride and dinitrogen monoxide? A) (rate of SF6 effusion) = 4.87 x (rate of NO effusion) B) the rates are the same since they are at the same temperature C) (rate of SF6 effusion) = 2.21 x (rate of NO effusion) D) (rate of SF6 effusion) = 0.45 x (rate of NO effusion) E) (rate of SF6 effusion) = 0.21 x (rate of NO effusion)
a) A 4.00L tank at 25.0° C is filled with 4.0 g of nitrogen monoxide (NO) and 8.3 g of sulfur hexafluoride gas (SF6). What is the mole fraction of sulfur hexafluoride? A) 0.17 B) 0.21 C) 0.48 D) 0.67 E) 0.30 F) 0.43 b) What is the ratio between the rates of effusion of sulfur hexafluoride and dinitrogen monoxide? A) (rate of SF6 effusion) = 4.87 x (rate of NO effusion) B) the rates are the same since they are at the same temperature C) (rate of SF6 effusion) = 2.21 x (rate of NO effusion) D) (rate of SF6 effusion) = 0.45 x (rate of NO effusion) E) (rate of SF6 effusion) = 0.21 x (rate of NO effusion)
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
a) A 4.00L tank at 25.0° C is filled with 4.0 g of nitrogen monoxide (NO) and 8.3 g of sulfur
hexafluoride gas (SF6). What is the mole fraction of sulfur hexafluoride?
A) 0.17
B) 0.21
C) 0.48
D) 0.67
E) 0.30
F) 0.43
b) What is the ratio between the rates of effusion of sulfur hexafluoride and dinitrogen
monoxide?
A) (rate of SF6 effusion) = 4.87 x (rate of NO effusion)
B) the rates are the same since they are at the same temperature
C) (rate of SF6 effusion) = 2.21 x (rate of NO effusion)
D) (rate of SF6 effusion) = 0.45 x (rate of NO effusion)
E) (rate of SF6 effusion) = 0.21 x (rate of NO effusion)
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