T 22.5°c p. 0450 atm Putting a lot of things together: the carbon tetrachloride problem CS:(g) + 3 Cl:(g) → CCl(g) + S:Cl2(g) Carbon tetrachloride, CCl(8), can be synthesized according to the reaction represented above. A chemist runs the reaction at a constant temperature of 135°C in a rigid 23.0 L container. (a) Draw a particle drawing of the reactants together in the container. Pay attention to ratios. Use this key: CS:(g) (b) Chlorine gas, Cla(g), is initially present in the container at a pressure of 0.45 atm. How many moles of Cla(g) are in the container? (c) How many grams of carbon disulfide, CSz(g), are needed to react completely with the Cl2(g)? (e) What is the density of the chlorine gas, Cl2(g), at the reaction conditions?
T 22.5°c p. 0450 atm Putting a lot of things together: the carbon tetrachloride problem CS:(g) + 3 Cl:(g) → CCl(g) + S:Cl2(g) Carbon tetrachloride, CCl(8), can be synthesized according to the reaction represented above. A chemist runs the reaction at a constant temperature of 135°C in a rigid 23.0 L container. (a) Draw a particle drawing of the reactants together in the container. Pay attention to ratios. Use this key: CS:(g) (b) Chlorine gas, Cla(g), is initially present in the container at a pressure of 0.45 atm. How many moles of Cla(g) are in the container? (c) How many grams of carbon disulfide, CSz(g), are needed to react completely with the Cl2(g)? (e) What is the density of the chlorine gas, Cl2(g), at the reaction conditions?
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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See attached worksheet. Temperature = 22.5 degrees C and Pressure = 0.950 atm.
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CCl4 is an ideal tetrahedral molecule with bond angle 109.5. Generally, it is a gas with no color and is of non-flammable nature. Since, it has a zero net dipole moment, so is a non-polar solvent, hence, not soluble in water.
Given:
Temperature, T = 22.5C = 295.65 K
Pressure, P = 0.950 atm
Volume, V = 23.00 L
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