Pentene (C5H10) reacts with ethanoic acid to form pentyl ethanoate, the equilibrium CH3CO2H + C5H10 ➡ CH3CO2C5H11 being established when a solution of 0.020 moles of pentene and 0.010 moles of acetic acid in 600cm3 of an inert solvent was allowed to reach equilibrium at 150C, 0.0090 moles of pentyl ethanoate was formed.How many moles of pentene and ethanoic acid were present in the solution after equilibrium had been attained?

The chemical equation for a reaction between pentene and ethanoic acid is CH3CO2H + C5H10…

Answered: Pentene (C5H10) reacts with ethanoic…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Pentene (C₅H₁₀) reacts with ethanoic acid to form pentyl ethanoate, the equilibrium CH₃CO₂H+ C₅H₁₀ ➡ CH₃CO₂C₅H₁₁ being established when a solution of 0.020 moles of pentene and 0.010 moles of acetic acid in 600cm³ of an inert solvent was allowed to reach equilibrium at 15⁰C, 0.0090 moles of pentyl ethanoate was formed.

How many moles of pentene and ethanoic acid were present in the solution after equilibrium had been attained?

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