Pentacontane is an unbranched alkane that contains 50 carbon atoms in each molecule. How many hydrogen atoms are present in each molecule of pentacontane? 102 100 52 150 50
Pentacontane is an unbranched alkane that contains 50 carbon atoms in each molecule. How many hydrogen atoms are present in each molecule of pentacontane? 102 100 52 150 50
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![### Pentacontane Question
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**Question:**
Pentacontane is an unbranched alkane that contains 50 carbon atoms in each molecule. How many hydrogen atoms are present in each molecule of pentacontane?
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**Answer Choices:**
- \( \circ \) 102
- \( \circ \) 100
- \( \circ \) 52
- \( \circ \) 150
- \( \circ \) 50
---
To solve this, we utilize the general formula for alkanes, which is \( C_nH_{2n+2} \).
Given that the number of carbon atoms (n) is 50, we can substitute this into the formula to find the number of hydrogen atoms:
\[ H = 2n + 2 = 2(50) + 2 = 100 + 2 = 102 \]
Thus, the correct answer is:
\( \circ \) 102](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F327c4acc-aab0-4600-9811-c42079067cf3%2Fded2e261-c15b-42f5-bbba-595fb235624e%2Ft9ynjh9_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Pentacontane Question
---
**Question:**
Pentacontane is an unbranched alkane that contains 50 carbon atoms in each molecule. How many hydrogen atoms are present in each molecule of pentacontane?
---
**Answer Choices:**
- \( \circ \) 102
- \( \circ \) 100
- \( \circ \) 52
- \( \circ \) 150
- \( \circ \) 50
---
To solve this, we utilize the general formula for alkanes, which is \( C_nH_{2n+2} \).
Given that the number of carbon atoms (n) is 50, we can substitute this into the formula to find the number of hydrogen atoms:
\[ H = 2n + 2 = 2(50) + 2 = 100 + 2 = 102 \]
Thus, the correct answer is:
\( \circ \) 102
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