Answered: Peg P is driven by the fork link OA… | bartleby

Related questions

Question

Peg P is driven by the fork link OA along the curved path described by r 2.8.8 ft. At the
instant = 1.3 rad, the angular velocity of the link is = 1.4 rad/s and the angular acceleration is
0=0.66 rad/s².
For peg P at this instant, please find:
radial acceleration a, a -10.55
transverse acceleration ag=
magnitude of total acceleration a=
m
m
m
5²

Expert Solution

Step by step

Solved in 4 steps with 9 images

SEE SOLUTION Check out a sample Q&A here

Blurred answer

Similar questions

A wheel, initially rotating at 15.4 rad/s, undergoes an angular acceleration of 5.5 rad/s^2. What is the angular velocity when the wheel has turned through an angle of 69.0 rad? Give your answer in rad/s.
An amusement park ride rotates around a fixed axis such that the angular position of a point on the ride follows the equation: θ(t) = a + bt2 – ct3 where a = 2.1 rad, b = 0.75 rad/s2 and c = 0.035 rad/s3. a. Determine an equation for the angular speed of the ride as a function of time, omega(t). Write your answet using the symbols a, b, and c, instead of their numerical values. b. Besides at t = 0, at what time t1 is the ride stopped? Give your answer in seconds. c. What is the magnitude of the angular displacement of the ride in radians between times t = 0 and t = t1? d. Determine an equation for the angular acceleration of the ride as a function of time, alpha(t). Write your answer using the symbols a, b, and c, instead of their numerical values. e. What is the angular acceleration in rad/s^2 when the ride is at rest t = t1?
A strap, rod, or something comparable is used to spin up the disc. I imagine someone hand-starting a lawnmower. If he pulls the strap with a final speed before pulling the strap away, what is the rotation rate of the disk, ω in rev/s? The moment of inertia of a disc is 1/2MR2. There's no sliding. Strap's final speed = v = 0.99 m/s. The disc's radius is R = 0.3 m The disc's mass is M = 0.8 kg
At time t= 0s, a wheel has an angular displacement of zero radians and an angular velocity of 29 radja The wheel has a constant acceleration of -0.52 radjs?. In this situation, the maximum value of the angular displacement, in rad, is closest to: OA. +1011 O B. +1617 OC. +1213 O D.+1415 O E. +809
A figure skater performs a twisting jump. She rotates around her longitudinal axis 2 times in 0.65 s. What was her average angular velocity in radians/second? A 720rad/s B 19.3rad/s C 4? rad/s D 9.67 rad/s E 1107 rad/s
The ball rolls without slipping up the incline and continues rolling at a constant but lower speed. Initial speed is vi = 2.62 m/s. The vertical height of the ramp is h = 0.47 m. There is no friction. What is the linear speed of the ball when it reaches the top of the ramp?
Item 21 Part A A child is pushing a merry-go-round. The angle through which the merry-go-round has turned varies with time according to 0(t) = yt+ Bt³, where y=0.450 rad/s and B= 0.0115 rad/s³. Calculate the angular velocity of the merry-go-round as a function of time. For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of Calculating angular velocity. Express your answer in terms of the variables B, y, and t. Πν ΑΣφ w:(t) = Submit Request Answer Part B What is the initial value of the angular velocity? Express your answer in radians per second. ? Wz = rad/s Submit Request Answer
The angular speed of a wheel decreases uniformly from 34.0 rad/s to 2.0 rad/s in 18.0 s.A. Find the constant angular acceleration in rad/s^2.B. Find the number of revolutions made by the wheel in this time.
I drive a Nissan Leaf to work. With the e-pedal on, the motor recovers energy through braking very aggressively. I need about 7 KW-hour to come to school if I use mostly the freeways. That’s about 5 KW-hour if I take mostly local streets. From the energy perspective, can you offer an explanation to explain this difference?
A cylinder is 0.4 m in radius and {h} m in length. Its rotational inertia, about the cylinder axis on which it is mounted, is 1.2 kg. m². A string is wound around the cylinder and pulled with a force of 4 N. The angular acceleration of the cylinder is: Answer:
A power drill starts from rest and undergoes uniform angular acceleration for a period of 0.175 s until it turns at a rate of 2.65 ✕ 104 rev/min.A.What is the drill's angular acceleration (in rad/s2)? (Enter the magnitude.)B. What is the angle (in radians) through which the drill rotates during this period? (Enter the magnitude.)
A rotating wheel requires 4.66 s to rotate through 45.9 rev. It’s angular speed at the end of the 4.66s interval is 66.2 rad/s. What is its constant angular acceleration? Assume the angular acceleration has the same sign as the angular velocity. Answer in units of rad/s^2.

SEE MORE QUESTIONS