(PEF-1) A uniform electric field with a magnitude of 2.50x10² N/C points in the +ydirection, as shown in the diagram below.(a) Find the potential difference between points A and B (VB-VA), in Volts.(b) Find the potential difference between points B and C (VC-VB), in Volts.(c) Find the potential difference between points C and A (Vc-VA), in Volts.(d) If an electron (m=9.11x10-31 kg, q=-1.60x10-19 C) is paced at rest atpoint B, what will its speed (in m/s) be when it reaches point A? Useconservation of energy.yB(3.00m, 5.50m) (9.00m, 5.50m)AC(3.00m, 1.50m)electricfield linesFox

GivenE=2.50×102 N/C(a)separation between point A and B, d=5.50-1.50 =4 mVB-VA=Ed…

Answered: (PEF-1) A uniform electric field with a…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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(PEF-1) A uniform electric field with a magnitude of 2.50x10² N/C points in the +y
direction, as shown in the diagram below.
(a) Find the potential difference between points A and B (VB-VA), in Volts.
(b) Find the potential difference between points B and C (VC-VB), in Volts.
(c) Find the potential difference between points C and A (Vc-VA), in Volts.
(d) If an electron (m=9.11x10-31 kg, q=-1.60x10-19 C) is paced at rest at
point B, what will its speed (in m/s) be when it reaches point A? Use
conservation of energy.
y
B
(3.00m, 5.50m) (9.00m, 5.50m)
A
C
(3.00m, 1.50m)
electric
field lines
Fox

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Step 1

$Given E = 2.50 \times 10^{2} N / C (a) separation between point A and B, d = 5.50 - 1.50 = 4 m V_{B} - V_{A} = Ed = - 2.50 \times 10^{2} \times 4 = - 10^{3} volts all conservative forces act in direction of decreasing potential energy so potential at A will be higher than potential at B (b) V_{c} = V_{B} as you are moving perpendicular to the field so you are neither gaining nor losing potential energy thus V_{C} - V_{B} = 0 volts$

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