Answered: 1. (a) What is the capacitance of a… | bartleby

Related questions

Question

1. (a) What is the capacitance of a parallel plate capacitor having plates of area 2 m² that are separated
by 0.02 mm of neoprene rubber (K = 6.7)?
C =
uF
(b) What charge does it hold when 9 V is applied to it?
Q =
C
(c) Compare this charge to the case when no dielectric is present.
The charge when no dielectric is present is
Qdielectric
is present.
no
- dielectric
compared to when a dielectric

Expert Solution

Step by step

Solved in 4 steps

SEE SOLUTION Check out a sample Q&A here

Blurred answer

Similar questions

Question 2 Consider a capacitor made with square plates that are 1 cm on a side, and separated by 0.01 mm, with paper (dielectric constant-3.6) between the plates. a) What is the capacitance of the capacitor?
4. Consider cylindrical coaxial structure having perfect conductors. Radius of inner and outer structures are given as r; = 1 cm and r2 = 2 cm, respectively. Area between the conductors is filled with a dielectric material e = 4€, and it is assumed that it does not contains any free charge. Voltage on the inner conductor is 50V and outer conductor is grounded (0V). a) Find the expression of electric potential in dielectric media by using Laplace's equation. b) Find the electric field from the electric potential. After that, use boundary condition to determine charge density Ps on the surface of the inner conductor.
2. Consider the Earth and a cloud lay : 800 m above the planet to be the plates of a parallel-plate capacitor. (a) If the cloud layer has an area of 1.6 km² = 1.6 x 10° m², what is the capacitance? (b) If an electric field strength greater than 3.0 x 10 N/C causes the air to break down and conduct charge (lightning), what is the maximum charge the cloud can hold?
First box choices are 4, 3, 6, 1, 2 (V) the second box choices are 1, 8, 3, 1.5, 6 (nJ) and the third box pick from I-V
A simple capacitor can be constructed from two conductive plates. Two conductive plates with an area of 10.0cm x 10.0 cm are held facing one another at a separation of 1.50 mm and 12.0 V is applied between them. a) Find the capacitance of this configuration b) Find the charge on the plates. c) How much energy is stored in the capacitor? d) How much energy can the capacitor store if a dielectric with K= 4.5 is inserted between the plates rather than air?
2 do only a) and b) parts of this question.
1. What is the capacitance of a parallel plate capacitor with metal plates, each of area 1.00 m², separated by 2.00 mm? What charge is stored in this capacitor if a voltage of 3.00 x 103 V is applied to it? 2. The capacitors have values C1 = 2.0 µF and C2 = 4.0 µF, C3 = 5.0 µF C4 = 7.0 µF and the potential difference across the battery is 9.0 V. Assume that the capacitors are connected in series. a) Find the equivalent capacitance of the circuit. b) Solve for the potential difference across each capacitors. 3. Given the same problem in #2. Assume that the capacitors are connected in parallel. a) Find the equivalent capacitance of the circuit. b) Solve for the charge across each capacitors.
Two parallel plate capacitors are connected to a 60 V battery as shown. C₁ is air filled and C₂ uses a dielectric material with relative permittivity/dielectric constant of -2.6. Each capacitor has a plate area of A = 80 cm² and a plate separation of 3.0 mm. a) Find the charge Q on the plates of by C₁ and C2. b) The energy stored by C₁, C2 and total energy stored. + 60V C₂ *Indicate all assumed voltage polarities C₁
Q. 14 : If a 4 µF capacitor is charged to 1 kV, then energy stored in the capacitor is (a) 1J (b) 4J (c) 6 J (d) 2J
Capacitance Problem 3: Two parallel plates have charges +Q and −Q, as shown. The magnitude of the charges is 29.7nC, the area of each plate is A=0.0105 m2, and the distance between them is d = 8.53cm. The plates are surrounded by air. Part (f) If the area is doubled to 2A while the gap is decreased to 14d, then what is the value, in picofarads, of the new capacitance? Part (g) What is the new value, in volts, of potential difference between the plates with the original charges, +Q and −Q, given the increased area and reduced gap of Part (f)?
a) A capacitor consists of two parallel metal plates immersed in a high-dielectric liquid, chloro- cyclohexane (e = 30). When the separation of the plates is 1mm, the capacitance is 0.06 F. Initially it is charged, at 500 V. Assume that 0 = 8.85 x 10-12 Fm-1. i) == Use this information to calculate the area of the plates, and the charge and the energy stored. ii) The plates are now pulled apart, to a gap of 1cm. Calculate the voltage it is now at, the energy now stored, and the force required to pull the plates apart.
Asap plz

SEE MORE QUESTIONS