peak /cie, instantaneous voltage v at the following angles: (a) 30° , (b) 120° , (c) 220° , (d) 210° , (e) 345° Answers: (a) v = 55V (b) v = 95.25 V (c) v = -70.70 V (d) v = -55 V (e) v = -28.47 V (3) Referring to the same AC voltage of Problem#(2) at what angles (from 0 to 720°) will the instantaneous voltage v be : (a) 90 V and (c) -60 V Answers: (a) 01= e, = 03 = O4 = degrees (b) Ө3 02 = O4 = degrees

Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Question
(2)
A sine wave voltage has peak value of 110Vp. For one cycle, what is the
instantaneous voltage v at the following angles:
(a) 30° , (b) 120° , (c) 220° , (d) 210° , (e) 345°
Answers: (a) v = 55V
(b) v = 95.25 V
(c) v = -70.70 V
(d) v = -55 V
(e) v = -28.47 V
Referring to the same AC voltage of Problem#(2) at what angles (from 0
to 720°) will the instantaneous voltage v be : (a) 90 V and (c) -60 V
(3)
Answers: (a) 01=
e, =
.03 =
O4 =
degrees
(b) Ө13
02 =
03 =
84 =
degrees
Transcribed Image Text:(2) A sine wave voltage has peak value of 110Vp. For one cycle, what is the instantaneous voltage v at the following angles: (a) 30° , (b) 120° , (c) 220° , (d) 210° , (e) 345° Answers: (a) v = 55V (b) v = 95.25 V (c) v = -70.70 V (d) v = -55 V (e) v = -28.47 V Referring to the same AC voltage of Problem#(2) at what angles (from 0 to 720°) will the instantaneous voltage v be : (a) 90 V and (c) -60 V (3) Answers: (a) 01= e, = .03 = O4 = degrees (b) Ө13 02 = 03 = 84 = degrees
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