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Peak A has a height of 90 mm and a width at half height of 5 while peak B has a height of 109 and a width at half height of 10. What is the percent composition of peak B? Please give your answer as a whole number and do not include "%".

Peak A has a height of 90 mm and a width at half height of 5 while peak B has a height of 109 and a width at half height of 10. What is the percent composition of peak B? Please give your answer as a whole number and do not include "%".

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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**Problem Statement:** Peak A has a height of 90 mm and a width at half height of 5. Peak B has a height of 109 and a width at half height of 10. What is the percent composition of peak B? Please give your answer as a whole number and do not include "%". **Explanation:** To find the percent composition of peak B, you need to calculate the area of each peak and then determine what percentage peak B's area is of the total area of both peaks. 1. **Calculate the Area of Each Peak:** - Assume the peaks are triangular for simplicity. - Area of a triangle = 0.5 * base * height. **Peak A:** - Height = 90 mm - Width at half height (Base) = 5 - Area of Peak A = 0.5 * 5 * 90 = 225 mm² **Peak B:** - Height = 109 - Width at half height (Base) = 10 - Area of Peak B = 0.5 * 10 * 109 = 545 mm² 2. **Calculate Total Area:** - Total Area = Area of Peak A + Area of Peak B - Total Area = 225 mm² + 545 mm² = 770 mm² 3. **Calculate Percent Composition of Peak B:** - Percent Composition of Peak B = (Area of Peak B / Total Area) * 100 - Percent Composition of Peak B = (545 / 770) * 100 ≈ 70.8 4. **Provide the Answer as a Whole Number:** - Therefore, the percent composition of peak B is approximately 71. Please input your answer in the provided box.
Transcribed Image Text:**Problem Statement:** Peak A has a height of 90 mm and a width at half height of 5. Peak B has a height of 109 and a width at half height of 10. What is the percent composition of peak B? Please give your answer as a whole number and do not include "%". **Explanation:** To find the percent composition of peak B, you need to calculate the area of each peak and then determine what percentage peak B's area is of the total area of both peaks. 1. **Calculate the Area of Each Peak:** - Assume the peaks are triangular for simplicity. - Area of a triangle = 0.5 * base * height. **Peak A:** - Height = 90 mm - Width at half height (Base) = 5 - Area of Peak A = 0.5 * 5 * 90 = 225 mm² **Peak B:** - Height = 109 - Width at half height (Base) = 10 - Area of Peak B = 0.5 * 10 * 109 = 545 mm² 2. **Calculate Total Area:** - Total Area = Area of Peak A + Area of Peak B - Total Area = 225 mm² + 545 mm² = 770 mm² 3. **Calculate Percent Composition of Peak B:** - Percent Composition of Peak B = (Area of Peak B / Total Area) * 100 - Percent Composition of Peak B = (545 / 770) * 100 ≈ 70.8 4. **Provide the Answer as a Whole Number:** - Therefore, the percent composition of peak B is approximately 71. Please input your answer in the provided box.
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