P(E₁) = P(E2) = P(E3)== 3. Also P(A/E)= 1, P(A/E2) 75 3 60 === 4 P(E3)= 100 100 miin 35 By Bayes' Theorem, P(E₁/A) = P(E₁) P(A/E₁) P(E,) P(A/E)+P(E,) P(A/E)+P(E2) P(A/E₂)
P(E₁) = P(E2) = P(E3)== 3. Also P(A/E)= 1, P(A/E2) 75 3 60 === 4 P(E3)= 100 100 miin 35 By Bayes' Theorem, P(E₁/A) = P(E₁) P(A/E₁) P(E,) P(A/E)+P(E,) P(A/E)+P(E2) P(A/E₂)
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter5: Inverse, Exponential, And Logarithmic Functions
Section5.3: The Natural Exponential Function
Problem 44E
Related questions
Question
Find P(E1/A)
Transcribed Image Text:P(E₁) = P(E2) = P(E3)== 3.
75
3
Also P(A/E)= 1, P(A/E2) = 100
By Bayes' Theorem,
P(E₁/A) =
60
"
4
P(E3)=
100
P(E₁) P(A/E₁)
315
P(E₁) P(A/E₁)+P(E2) P(A/E2)+P(E3) P(A/E3)
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by step
Solved in 3 steps with 3 images
Recommended textbooks for you
Algebra & Trigonometry with Analytic Geometry
Algebra
ISBN:
9781133382119
Author:
Swokowski
Publisher:
Cengage
Algebra & Trigonometry with Analytic Geometry
Algebra
ISBN:
9781133382119
Author:
Swokowski
Publisher:
Cengage