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P(E₁) = P(E2) = P(E3)== 3. Also P(A/E)= 1, P(A/E2) 75 3 60 === 4 P(E3)= 100 100 miin 35 By Bayes' Theorem, P(E₁/A) = P(E₁) P(A/E₁) P(E,) P(A/E)+P(E,) P(A/E)+P(E2) P(A/E₂)

P(E₁) = P(E2) = P(E3)== 3. Also P(A/E)= 1, P(A/E2) 75 3 60 === 4 P(E3)= 100 100 miin 35 By Bayes' Theorem, P(E₁/A) = P(E₁) P(A/E₁) P(E,) P(A/E)+P(E,) P(A/E)+P(E2) P(A/E₂)

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter5: Inverse, Exponential, And Logarithmic Functions
Section5.3: The Natural Exponential Function
Problem 44E
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Find P(E1/A)

P(E₁) = P(E2) = P(E3)== 3. 75 3 Also P(A/E)= 1, P(A/E2) = 100 By Bayes' Theorem, P(E₁/A) = 60 " 4 P(E3)= 100 P(E₁) P(A/E₁) 315 P(E₁) P(A/E₁)+P(E2) P(A/E2)+P(E3) P(A/E3)
Transcribed Image Text:P(E₁) = P(E2) = P(E3)== 3. 75 3 Also P(A/E)= 1, P(A/E2) = 100 By Bayes' Theorem, P(E₁/A) = 60 " 4 P(E3)= 100 P(E₁) P(A/E₁) 315 P(E₁) P(A/E₁)+P(E2) P(A/E2)+P(E3) P(A/E3)
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