PC15(9) PC13(g) + Cl2(g) 6) PCI, is added. Choose (endothermic) 7) Chlorine gas (Cl₂) is removed. Choose

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Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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For questions 6,7,8,9 Determine what shift would be made according to the chemical reaction above. Options: Shift left, Shift Right, or no shift
## Equilibrium Reactions and Factors Affecting Them

### Chemical Equation:
\[ \text{PCl}_5(g) \rightleftharpoons \text{PCl}_3(g) + \text{Cl}_2(g) \]
**(endothermic reaction)**

### Scenarios:

#### 6)
**Scenario:** PCl\(_5\) is added.

**Response Options:** 
- Choose (dropdown menu)

Explanation: Adding more PCl\(_5\) will increase the concentration of reactants and will shift the equilibrium to the right, favoring the formation of PCl\(_3\) and Cl\(_2\).

#### 7)
**Scenario:** Chlorine gas (Cl\(_2\)) is removed.

**Response Options:** 
- Choose (dropdown menu)

Explanation: Removing Cl\(_2\) will decrease the concentration of one of the products and will shift the equilibrium to the right to compensate and form more PCl\(_3\) and Cl\(_2\).

#### 8)
**Scenario:** System is warmed (heat added).

**Response Options:**
- Choose (dropdown menu)

Explanation: Since the reaction is endothermic, adding heat will shift the equilibrium to the right, favoring the production of PCl\(_3\) and Cl\(_2\).

#### 9)
**Scenario:** Pressure is decreased.

**Response Options:** 
- Choose (dropdown menu)

Explanation: Decreasing the pressure will shift the equilibrium towards the side with more gas molecules. Here, there are more molecules on the right side (PCl\(_3\) + Cl\(_2\)), so the equilibrium shifts to the right.

### Diagram/Graph Explanation:
No diagrams or graphs are present in the provided image. The explanation is based on textual information and reaction principles.
Transcribed Image Text:## Equilibrium Reactions and Factors Affecting Them ### Chemical Equation: \[ \text{PCl}_5(g) \rightleftharpoons \text{PCl}_3(g) + \text{Cl}_2(g) \] **(endothermic reaction)** ### Scenarios: #### 6) **Scenario:** PCl\(_5\) is added. **Response Options:** - Choose (dropdown menu) Explanation: Adding more PCl\(_5\) will increase the concentration of reactants and will shift the equilibrium to the right, favoring the formation of PCl\(_3\) and Cl\(_2\). #### 7) **Scenario:** Chlorine gas (Cl\(_2\)) is removed. **Response Options:** - Choose (dropdown menu) Explanation: Removing Cl\(_2\) will decrease the concentration of one of the products and will shift the equilibrium to the right to compensate and form more PCl\(_3\) and Cl\(_2\). #### 8) **Scenario:** System is warmed (heat added). **Response Options:** - Choose (dropdown menu) Explanation: Since the reaction is endothermic, adding heat will shift the equilibrium to the right, favoring the production of PCl\(_3\) and Cl\(_2\). #### 9) **Scenario:** Pressure is decreased. **Response Options:** - Choose (dropdown menu) Explanation: Decreasing the pressure will shift the equilibrium towards the side with more gas molecules. Here, there are more molecules on the right side (PCl\(_3\) + Cl\(_2\)), so the equilibrium shifts to the right. ### Diagram/Graph Explanation: No diagrams or graphs are present in the provided image. The explanation is based on textual information and reaction principles.
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