Pay your taxes: According to the Internal Revenue Service, the proportion of federal tax returns for which no tax was paid was p=0.326. As part of a taxEspañolaudit, tax officials draw a simple sample of n=120 tax returns. Use O Cumulative Normal Distribution Table as needed. Round your answers to at least fourdecimal places if necessary.Part 1 of 400(a) What is the probability that the sample proportion of tax returns for which no tax was paid is less than 0.31?The probability that the sample proportion of tax returns for which no tax was paid is less than 0.31 isPart 2 of 4(b) What is the probability that the sample proportion of tax returns for which no tax was paid is between 0.38 and 0.40?The probability that the sample proportion of tax returns for which no tax was paid is between 0.38 and 0.40 isPart 3 of 4(c) What is the probability that the sample proportion of tax returns for which no tax was paid is greater than 0.34?Book1The probability that the sample proportion of tax returns for which no tax was paid is greater than 0.34 isGOCTостO 10989MacBook AirDIIF10888FOFSF4F3&%23$97235

According to the Internal Revenue Service, the proportion of federal tax returns for which no tax…

Answered: Pay your taxes: According to the…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Electricity bills: According to a government energy agency, the mean monthly household electricity bill in the United States in 2011 was $108.87 . Assume the amounts are normally distributed with standard deviation $18.00 . Use the TI-84 Plus calculator to answer the following. (a) What proportion of bills are greater than $134 ? (b) What proportion of bills are between $83 and $145 ? (c) What is the probability that a randomly selected household had a monthly bill less than $118 ? Round the answers to at least four decimal places. Part 1 of 3 The proportion of bills that are greater than $134 is . Part 2 of 3 The proportion of bills that are between $83 and $145 is . Part 3 of 3 The probability that a randomly selected household had a monthly bill less than $118 is .
The state test scores for 12randomly selected high school seniors are shown on the right. Complete parts (a) through (c) below. Assume the population is normally distributed. 1428 1228 980 698 725 831 723 742 550 624 1446 946 (a) Find the sample mean. x=enter your response here (Round to one decimal place as needed.)
Which of the following sampling methods was used in the study described below? A researcher is interested in knowing how many hours a week teenagers spend on social media. He surveys his daughter, who is a teenager, and fifty of her teen friends. a. simple random sample b. systematic sample c. convenience sample d. self-selected sample
Find the Mean and variance for the prompts below: State Farm Insurance Company reports that approximately 65% of all automobile damage liability claims are made by people under 20 years of age. A random sample of fifteen automobile insurance claims are under study.
Consider a binomial distribution. About 61% of all Salinas residents own a smart phone. Find the mean number of residents own a smart phone when selecting a sample of n = 53 residents.
study the effectiveness of a recent advertising campaign for a new menu item, a restaurant asks every fifth customer about their awareness of the new item. What type of sample is this? A. A judgment sample. B. A cluster sample. C. A convenience sample. D. A simple random sample. E. A systematic sample.
Electricity bills: According to a government energy agency, the mean monthly household electricity bill in the United States in 2011 was $108.87 . Assume the amounts are normally distributed with standard deviation $18.00 . Use the TI-84 Plus calculator to answer the following. (a) What proportion of bills are greater than $134 ? (b) What proportion of bills are between $83 and $145 ? (c) What is the probability that a randomly selected household had a monthly bill less than $118 ? Round the answers to at least four decimal places. Part 1 of 3 The proportion of bills that are greater than $134 is . Part 2 of 3 The proportion of bills that are between $83 and $145 is . Part 3 of 3 The probability that a randomly selected household had a monthly bill less than $118 is .
Pay your taxes: According to the Internal Revenue Service, the proportion of federal tax returns for which no tax was paid was p=0.326. As part of a tax audit, tax officials draw a simple sample of n=140 tax returns. Use Cumulative Normal Distribution Table as needed. Round your answers to at least four decimal places if necessary. Part 1 of 4 (a) What is the probability that the sample proportion of tax returns for which no tax was paid is less than 0.32? The probability that the sample proportion of tax returns for which no tax was paid is less than 0.32 is Part 2 of 4 (b) What is the probability that the sample proportion of tax returns for which no tax was paid is between 0.37 and 0.40? The probability that the sample proportion of tax returns for which no tax was paid is between 0.37 and 0.40 is
Suppose a sample of O-rings was obtained and the wall thickness (in inches) of each was recorded. Use a normal probability plot to assess whether the sample data could have come from a population that is normally distributed. 0.163 0.182 0.194 0.211 0.224 0.225 0.233 0.243 0.251 0.259 0.271 0.273 0.295 0.307 0.317 0.340 Click here to view the table of critical values for normal probability plots. Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table. Using the correlation coefficient of the normal probability plot, is it reasonable to conclude that the population is normally distributed? Select the correct choice below and fill in the answer boxes within your choice. (Round to three decimal places as needed.) A. No. The correlation between the expected z-scores and the observed data, normal population. does not exceed the critical value, Therefore, it is not reasonable to conclude that the data come from…
It is generally believed that nearsightedness affectsabout 12% of all children. A local elementary school registered 133 incoming kindergarteners. Part A: Describe the sampling distribution model for the sample proportion by identifying its shape and telling its mean and standard deviation.Part B: What is the probability that more than 15% of the incoming kindergarteners are nearsighted?
A random survey asked respondents about their current annual salaries. The results are given in the table below. Salary Range Below $18,000 $18,000-$27,999 Number of Respondents 25 43 $28,000-$35,999 51 $36,000-$45,999 57 $46,000-$59,999 41 $60,000-$79,999 38 $80,000-$99,999 23 $100,000 or more 13 If a respondent from the survey is selected at random, compute the probability of the following. (Enter your probability as a fraction.) The respondent earns less than $36,000 annually.
Find the mean, median, and mode for a random sample of eight U.S. corporations with the following percentage changes in earnings per share in the current year compared with the previous year: 0% 0% 8.1% 13.6% 19.4% 20.7% 10.0% 14.2%

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