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PATH RADIUS An electron (with mass of 9.11x10-31 ka) moves through a cathode-ray tube at 2.0x10' m/s perpendicular to a magnetic field of 3,5x10-3 T. The electric field is turmed on. What is the radius of the electron's circular path? 1 ANALYZE AND SKETCH THE RROD

PATH RADIUS An electron (with mass of 9.11x10-31 ka) moves through a cathode-ray tube at 2.0x10' m/s perpendicular to a magnetic field of 3,5x10-3 T. The electric field is turmed on. What is the radius of the electron's circular path? 1 ANALYZE AND SKETCH THE RROD

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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I need an explanation on this and how to solve it using the calculator because i always get a different answer, also is the q equation: Q=1.602x10^-19 Or Q= -1.602x10^-19 Thanks in advance
of , he the EXAMPLE 1 PATH RADIUS An electron (with mass of 9.11x10-31 ka) moves through a cathode-ray tube 2.0x10 m/s perpendicular to a magnetic field of 3,5x10-3 T. The electric field is tumed om What is the radius of the electron's circular path? ormed ance, nd 1 ANALYZE AND SKETCH THE PROBLEM BO • Draw the path of the electron and label the velocity (v). lating • Sketch the magnetic field perpendicular to the velocity. he Diagram the force acting on the electron. Add the unknown quantity r of the electron's path. nents ed KNOWN UNKNOWN bert v = 2.0x107 m/s r = ? ame B = 3.5x10-3 T m = me = 9.11×10-31 kg q = e = -1.602×10-19 C ced. 2 SOLVE FOR THE UNKNOWN Use Newton's second law of motion to describe an electron in a cathode-ray tube subjected to a magnetic field. mv2 Bqv = le. mv r = Bq (9.11x10-31 kg)(2.0x107 m/s) (3.5x10-3 T)(-1.602×10-19 C) 4 Subslitute m= 9.11X10¬31 kg, v= 2.0X107 m/s, B = 3.5X10-3T, q=-1.602X10-19 C. nt = -3.2x10-2 m led 3 EVALUATE THE ANSWER • Are the units correct? The radius of the circular path is a length measurement, given in units of meters. • Are the values reasonable? Radii of a few centimeters are typical of this kind of apparatus and can easily be measured. The negative sign means that the circle curves in the direction opposite that of a positive ion. S. 1E
Transcribed Image Text:of , he the EXAMPLE 1 PATH RADIUS An electron (with mass of 9.11x10-31 ka) moves through a cathode-ray tube 2.0x10 m/s perpendicular to a magnetic field of 3,5x10-3 T. The electric field is tumed om What is the radius of the electron's circular path? ormed ance, nd 1 ANALYZE AND SKETCH THE PROBLEM BO • Draw the path of the electron and label the velocity (v). lating • Sketch the magnetic field perpendicular to the velocity. he Diagram the force acting on the electron. Add the unknown quantity r of the electron's path. nents ed KNOWN UNKNOWN bert v = 2.0x107 m/s r = ? ame B = 3.5x10-3 T m = me = 9.11×10-31 kg q = e = -1.602×10-19 C ced. 2 SOLVE FOR THE UNKNOWN Use Newton's second law of motion to describe an electron in a cathode-ray tube subjected to a magnetic field. mv2 Bqv = le. mv r = Bq (9.11x10-31 kg)(2.0x107 m/s) (3.5x10-3 T)(-1.602×10-19 C) 4 Subslitute m= 9.11X10¬31 kg, v= 2.0X107 m/s, B = 3.5X10-3T, q=-1.602X10-19 C. nt = -3.2x10-2 m led 3 EVALUATE THE ANSWER • Are the units correct? The radius of the circular path is a length measurement, given in units of meters. • Are the values reasonable? Radii of a few centimeters are typical of this kind of apparatus and can easily be measured. The negative sign means that the circle curves in the direction opposite that of a positive ion. S. 1E
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