A philanthropic organization sent free mailing labels and greeting cards to a random sample of 100,000 potential donors on their mailing list and received 4973 donations They havehad a contribution rate of 5% in past campaigns, but a staff member worries that the rate will be lower if they run this campaign as currently designed Complete parts a through cbelow. Assume the independence assumption is metA H₂ p=005HA P<0.05OD. Ho p=005HA P >0.05OB. H₂ p>0.05HA P 0.05A. The success/failure condition is metB. The randomization condition is metC. The 10% condition is met iD. The independence assumption is metCE H₂ P<0.05HA P=0.05b) Are the assumptions and conditions for inference met?Which assumptions and conditions below are met? Select all that applyOCH₂ P=0.05HA P 005XFH₂p005HA P-005

The true proportion (p) = 0.05sample size(n)=1,00,000x=4973sample proportion p^ =x/n…

Answered: past campaigns sume the independence…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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6 X 01:13:24 eBook Quality Progress, February 2005, reports on improvements in customer satisfaction and loyalty made by Bank of America. A key measure of customer satisfaction is the response (on a scale from 1 to 10) to the question: "Considering all the business you do with Bank of America, what is your overall satisfaction with Bank of America?" Here, a response of 9 or 10 represents "customer delight." Suppose that the survey selected 480 customers. Assume that 45% of Bank of America customers would currently express customer delight. That is, assume p = .45. (a) Find the probability that the sample proportion obtained from the sample of 480 Bank of America customers would be within three percentage points of the population proportion. That is, find P(.42 ≤ § ≤ .48). (Round your answer to 4 decimal places. Do not round intermediate values. Round z-value to 2 decimal places.) P(.42 ≤ ≤.48)
T-Mobile Wi-Fi ? 1 9:38 AM • 47% Done 9 of 14 931 A IX H FOL O a F T e st.dent.desmes.com/sctivitybulderistudent80ta0000a2e4a0cba771034screeride-5 w IG| + ! Apps 6 Cuteuran Cen Claa Domy she.. O Emolyment Cente Lagn Sanin ispiratin Update + Legn Sanion ipratken. Seling Asacriste signi P k Fort Pres = Mid-Unit IV Assessment Siynin O sng adticn. O Suu Dastiny Cteagu 5o1 Nex > Question 4 A representativo sample of oak trees in a forest shows the trees to have a moan circumference of 19,7 inches and a standard deviation of 1.3 inchca Assuming the çircumferences are normally distributed, estimate the proportion of oak trees in this forest that have a circumference greator then 21 inches. Submit 23 * + 4 6 8. delete E R Y U 1 S D F G H J L re V B M ol option command command option !! ... .. ..
Method p: event proportion Exact method is used for this analysis. Descriptive Statistics N Event Sample p 50% lower bound for p 30 10 0.333333 0.318721 Test Null hypothesis H₀: p = 0.5 Alternative hypothesis H₁: p > 0.5 P-Value 0.979 9. What was your critical value? In what case would you have 2 critical values? 10. What was your test statistic? How many formulas are there for test statistics? How do you determine which to use for a specific problem? 11. What is your p-value? How does it compare to your level of significance? 12. What was your verdict? Did you decide to REJECT the NULL HYPOTHESIS or FAIL to REJECT the NULL HYPOTHESIS? How did you make that determination? Please show how you ended up getting those answers
EXAMPLE A civil engineer is interested in determining whether four different methods of estimating flood flow frequency pro- duce equivalent estimates of peak discharge when applied to the same watershed. Each procedure is used six times on the watershed, and the resulting discharge data (in cubic feet per second) are shown Estimation Method Observations 1 0.34 0.12 1.23 0.70 1.75 0.12 2 0.91 2.94 2.14 2.36 2.86 4.55 3 6.31 8.37 9.75 6.09 9.82 7.24 4 17.15 11.82 10.95 17.20 14.35 16.82
SAMPLE NAME pH EC DATE SAMPLED Effluent 1 7.1 80 27/02/2020 Effluent 2 5.1 410 27/02/2020 Effluent 3 5.0 1400 27/02/2020 Effluent 1 7.0 80 25/01/2020 Effluent 2 6.5 730 25/01/2020 Effluent 3 7.1 800 25/01/2020 Effluent 1 7.2 400 24/12/2019 Effluent 2 6.9 700 24/12/2019 Effluent 3 7.2 790 24/12/2019 Effluent 1 7.1 250 23/11/2019 Effluent 2 6.8 750 23/11/2019 Effluent 3 7.0 800 23/11/2019 Effluent 1 7.0 350 25/10/2019 Effluent 2 6.9 810 25/10/2019 Effluent 3 7.1 810 25/10/2019 Effluent 1 7.0 750 28/09/2019 Effluent 2 7.0 350 28/09/2019 Effluent 3 7.0 770 28/09/2019 Effluent 1 7.0 750 25/08/2019 Effluent 2 7.0 350 25/08/2019 Effluent 3 7.0 750 25/08/2019 Effluent 1 7.0 350 27/07/2019 Effluent 2 7.1 680 27/07/2019 Effluent 3 6.8 760 27/07/2019 Effluent 1 7.2 400 27/06/2019 Effluent 2 6.8 650 27/06/2019 Effluent 3 6.7 760 27/06/2019 Effluent 1 7.0 350 26/05/2019 Effluent 2 6.9 750 26/05/2019 Effluent 3 7.0 770 26/05/2019 Effluent…
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- PG Campus B Assessment 2 - MM207X Course X -pace.com/d2l/le/content/62284/viewContent/5264566/View Maps ne Left:1:47:37 Alexus Bloom: Attempt 1 The table below shows annual salary, s, rounded to the nearest dollar for 70 workers. What is the cumulative relative frequency for workers making less than or equal to 20000? Round your answer to 2 decimal places. Salary, s, in dollars Frequency 14000 < s < 33 16000 16000 < s < 18000 18000 < s < 20000 20000 < s s 22000 19 12 0.91 0.74 0.47 99+ 6)
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35 Score: 10.33/15 Question 13 ▾ No Comments 0/1 pt 3 2 Details ollege sources You want to obtain a sample to estimate a population proportion. At this point in time, you have no reasonable estimate for the population proportion. You would like to be 99% confident that your estimate is within 2.5% of the true population proportion. How large of a sample size is required? n = Services Do not round mid-calculation. However, a critical value rounded to two or three decimal places will suffice. Submit Question
CHI-SQUARE TEST The Chi-square test will be used to compare phenotypic values derived from the actual crosses to the expected values from the theoretical crosses. This test is a simple statistical test to evaluate the amount of deviation from the expected equal frequency ratio in cach class The chi-square test can be used to test any ratio goodness of fit. The calculated chi-square value is obtained by the formula: X =E (O-E)/E. Where, O- observed number on the actual cross; observed value E- calculated or expected frequency (from the corresponding theoretical cross) E- summation symbol which means that you'll have to perform a calculation for every single data item in your data set. ОВJЕСTIVES The students should be able to: a. To compare phenotypic data derived from actual crosses to expected values using the Chi-square test b. To be able to interpret the results of chi-square values derived from computations of monohybrid crosses MATERIALS Observed data from the Monohybrid…
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past campaigns sume the independence assumption is met P=005 P<0.05 P=005 P>0.05 OB H₂ p>0.05 H₁ P=0.05 CE H₂ p<0.05 H₂ P=005 assumptions and conditions for inference met? sumptions and conditions below are met? Select all that apply rate: be lower campag aign OCH₂ H₂ X5 M₂ НА