03 (b) What is the approximate probability that x will be within 0.6 of the population mean µ? le determined the mean and standard deviation of the sampling distribution of x. H-80 -= 1.25 le also determined that the sampling distribution of x is approximately normal, so we can calculate the desired probability by standardizing. Recall the standardization formula. 3)=P(258-12) P(x s a) = other words, we need to find the following. (x within 0.6 of population mean) = P((80-0.6) ≤x≤ (80+ 0.6✔ - P79.4 ≤ x ≤ 80.6✔ 80.6) LUSE SALT 79.4 - 80 1.25 = P-0.48 sz s 0.48 - Pz ≤ 0.48✔ 525 Submit Skip (you cannot come back) 80.6 within 0.6 of population mean) = P(z ≤ 0.48) - P(Z -0.48) 0.3688 X-0.3156 0.0532 x 1.25 0.48 04 se SALT to find the cumulative probability associated with a particular z-score, rounding the result to four decimal places. 0.6 80.680 0.48 - P(z s-0.48)