Answer STEP 6 PLEASE TY Step 3(b) What is the approximate probability that will be within 0.6 of the population mean u?We determined the mean and standard deviation of the sampling distribution of X.H-800 = 1.25XWe also determined that the sampling distribution of X is approximately normal, so we can calculate the desired probability by standardizing. Recall the standardization formula.P(x ≤ a) =)=P(2=²-1=²)XIn other words, we need to find the following.P(x within 0.6 of population mean) = P((80 - 0.6) ≤ x ≤ (80 + 0.6✔ 0.6= P(79.4 ≤ x ≤ 80.6 ✔80.6= P(75Submit79.4801.25Skip (you cannot come back)≤Z≤= P(-0..= Pz≤ 0.48 ✔=-0.48 z≤ 0.4880.6✔Step 4Use SALT to find the cumulative probability associated with a particular z-score, rounding the result to four decimal places.USE SALT<P(x within 0.6 of population mean) = P(Z ≤ 0.48) - P(z ≤ -0.48)= 0.36880.3156x0.0532X80.6 - 801.250.48)0.48 ]) - P(Z ≤ -0.48)

Find P(Z≤0.48)-P(Z≤-0.48)=?

03 (b) What is the approximate probability that x will be within 0.6 of the population mean µ? le determined the mean and standard deviation of the sampling distribution of x. H-80 -= 1.25 le also determined that the sampling distribution of x is approximately normal, so we can calculate the desired probability by standardizing. Recall the standardization formula. 3)=P(258-12) P(x s a) = other words, we need to find the following. (x within 0.6 of population mean) = P((80-0.6) ≤x≤ (80+ 0.6✔ - P79.4 ≤ x ≤ 80.6✔ 80.6) LUSE SALT 79.4 - 80 1.25 = P-0.48 sz s 0.48 - Pz ≤ 0.48✔ 525 Submit Skip (you cannot come back) 80.6 within 0.6 of population mean) = P(z ≤ 0.48) - P(Z -0.48) 0.3688 X-0.3156 0.0532 x 1.25 0.48 04 se SALT to find the cumulative probability associated with a particular z-score, rounding the result to four decimal places. 0.6 80.680 0.48 - P(z s-0.48)