particular county employs three assessors who are responsible for determining the value of residential property in the county. To see whether these assessors differ systematically in their assessments, 5 houses are selected, and each assessor is asked to determine the market value of each house. actor A denoting assessors (1-3) and factor B denoting houses (J5), suppose SSA 11.6, SSB 113, and SSE - 25.8. (a) Test H: ₁₂0 at level 0.05. (H, states that there are no systematic differences among assessors.) Calculate the test statistic. (Round your answer to two decimal places.) f -2.70 7x
particular county employs three assessors who are responsible for determining the value of residential property in the county. To see whether these assessors differ systematically in their assessments, 5 houses are selected, and each assessor is asked to determine the market value of each house. actor A denoting assessors (1-3) and factor B denoting houses (J5), suppose SSA 11.6, SSB 113, and SSE - 25.8. (a) Test H: ₁₂0 at level 0.05. (H, states that there are no systematic differences among assessors.) Calculate the test statistic. (Round your answer to two decimal places.) f -2.70 7x
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
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Problem 1P
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A particular county employs three assessors who are responsible for determining the value of residential property in the county. To factor \( A \) denoting assessors (\( I = 3 \)) and factor \( B \) denoting houses (\( J = 5 \)), suppose SSA = 11.6, SSB = 113, and SSE = 25.8.
(a) Test \( H_0: \mu_1 = \mu_2 = \mu_3 \) at level 0.05. (\( H_0 \) states that there are no systematic differences among assessors.)
Calculate the test statistic. (Round your answer to two decimal places.)
\( f = 2.70 \) ❌
**Explanation:**
The problem involves testing whether there are systematic differences among three assessors' evaluations by using the Analysis of Variance (ANOVA) method. The key components of the problem are the sums of squares: SSA (Sum of Squares for Assessor), SSB (Sum of Squares for Houses), and SSE (Sum of Squares for Error). These values are used to calculate a test statistic (\( f \)) to evaluate the null hypothesis.
The computed \( f \)-value is 2.70, but it appears that this value is incorrect as indicated by the ❌. The objective is to compare this value with a critical value from an \( f \)-distribution table to determine if the null hypothesis should be rejected.
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