Part II. Data Table Al 40.90g 92.55 l00°C symbol of metal used mass of empty 8" test tube mass of test tube and metal initial temperature of metal mass of water in Styrofoam cup 75,00g 21.2°C 31.4°C_ I cal initial temperature of water final temperature of metal and water mix specific heat of water specific heat of your metal from handbook ,900 Calculations (Carry out to the proper number of signiflcant digits.) 1. Mass of metal used. 92.5g -90.90g = 5l.6g ら.65 2. Change in temperature of metal. MCAT =- mcAT 68.6 (Sl,@(I) (3.4-21.2) =.-51,66) () %3D 10.2 3. Mass of water used. 75.00 4. Change in temperature of water. 10,2 5. Heat gained by water. 32,000 6. Calculated specific heat of metal. 51.66 7. Percentage error of experiment.

Chemistry
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### Heat Capacity Lab Report

#### Part II. Data Table
- **Symbol of metal used:** Al
- **Mass of empty 8'' test tube:** 40.90 g
- **Mass of test tube and metal:** 92.5 g
- **Initial temperature of metal:** 106°C
- **Mass of water in Styrofoam cup:** 75.00 g
- **Initial temperature of water:** 21.2°C
- **Final temperature of metal and water mix:** 31.4°C
- **Specific heat of water:** 1 cal/g°C
- **Specific heat of your metal from handbook:** 0.900 J/g°C

#### Calculations (Carry out to the proper number of significant digits)

1. **Mass of metal used:**
    \[
    92.5 \, \text{g} - 40.90 \, \text{g} = 51.6 \, \text{g}
    \]

2. **Change in temperature of metal:**
    \[
    \Delta T_{\text{metal}} = 106 \, \text{°C} - 31.4 \, \text{°C} = 74.6 \, \text{°C}
    \]

3. **Mass of water used:**
    \[
    75.00 \, \text{g}
    \]

4. **Change in temperature of water:**
    \[
    \Delta T_{\text{water}} = 31.4 \, \text{°C} - 21.2 \, \text{°C} = 10.2 \, \text{°C}
    \]

5. **Heat gained by water:**
    \[
    q_{\text{water}} = m_{\text{water}} \times c_{\text{water}} \times \Delta T_{\text{water}}
    \]
    \[
    q_{\text{water}} = 75.00 \, \text{g} \times 1 \, \text{cal/g°C} \times 10.2 \, \text{°C} = 765 \, \text{cal}
    3200
    \]

6. **Calculated specific heat of metal:**
    Using the heat gained by water, assuming no heat loss to the surroundings:
Transcribed Image Text:### Heat Capacity Lab Report #### Part II. Data Table - **Symbol of metal used:** Al - **Mass of empty 8'' test tube:** 40.90 g - **Mass of test tube and metal:** 92.5 g - **Initial temperature of metal:** 106°C - **Mass of water in Styrofoam cup:** 75.00 g - **Initial temperature of water:** 21.2°C - **Final temperature of metal and water mix:** 31.4°C - **Specific heat of water:** 1 cal/g°C - **Specific heat of your metal from handbook:** 0.900 J/g°C #### Calculations (Carry out to the proper number of significant digits) 1. **Mass of metal used:** \[ 92.5 \, \text{g} - 40.90 \, \text{g} = 51.6 \, \text{g} \] 2. **Change in temperature of metal:** \[ \Delta T_{\text{metal}} = 106 \, \text{°C} - 31.4 \, \text{°C} = 74.6 \, \text{°C} \] 3. **Mass of water used:** \[ 75.00 \, \text{g} \] 4. **Change in temperature of water:** \[ \Delta T_{\text{water}} = 31.4 \, \text{°C} - 21.2 \, \text{°C} = 10.2 \, \text{°C} \] 5. **Heat gained by water:** \[ q_{\text{water}} = m_{\text{water}} \times c_{\text{water}} \times \Delta T_{\text{water}} \] \[ q_{\text{water}} = 75.00 \, \text{g} \times 1 \, \text{cal/g°C} \times 10.2 \, \text{°C} = 765 \, \text{cal} 3200 \] 6. **Calculated specific heat of metal:** Using the heat gained by water, assuming no heat loss to the surroundings:
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