Part II. Balance the given REDOX reactions using the half-reaction method or ion- electron method. 1. Pb(OH)42+ CIO- → PbO2 + Cl + OH- in basic solution 2. Crl3+ Cl2 → CrO4²- + 104 + Cl in basic solution 3. Fe2+ (aq) + MnO4 (aq) Fe³+ (aq) + Mn²+ (aq) in basic medium Sb2S3 + H+ + NO3 → Sb2O5 + HSO4 + NO in acidic solution 4. Cr202-7(aq) + C2H5OH(1)→ Cr³+ (aq) + CO₂(g) in acidic solution 5.
Part II. Balance the given REDOX reactions using the half-reaction method or ion- electron method. 1. Pb(OH)42+ CIO- → PbO2 + Cl + OH- in basic solution 2. Crl3+ Cl2 → CrO4²- + 104 + Cl in basic solution 3. Fe2+ (aq) + MnO4 (aq) Fe³+ (aq) + Mn²+ (aq) in basic medium Sb2S3 + H+ + NO3 → Sb2O5 + HSO4 + NO in acidic solution 4. Cr202-7(aq) + C2H5OH(1)→ Cr³+ (aq) + CO₂(g) in acidic solution 5.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![Part II. Balance the given REDOX reactions using the half-reaction method or ion-
electron method.
1. Pb(OH)42+CIO → PbO2 + Cl + OH in basic solution
-
2. Crl3 + Cl2 → CrO42- + 104 + Cl in basic solution
3. Fe2+ (aq) + MnO4 (aq) Fe³+ (aq) + Mn²+ (aq) in basic medium
4. Sb2S3 + H+ + NO3
Sb2O5 + HSO4 + NO in acidic solution
Cr202-7(aq) + C₂H5OH(1)→ Cr³+ (aq) + CO₂(g) in acidic solution
5.
-](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3793f3d7-bee1-497e-96fc-dc6876135f1e%2F9fe9b6cf-a416-4d43-839e-2bba15ab0cec%2Fv3jgkln_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Part II. Balance the given REDOX reactions using the half-reaction method or ion-
electron method.
1. Pb(OH)42+CIO → PbO2 + Cl + OH in basic solution
-
2. Crl3 + Cl2 → CrO42- + 104 + Cl in basic solution
3. Fe2+ (aq) + MnO4 (aq) Fe³+ (aq) + Mn²+ (aq) in basic medium
4. Sb2S3 + H+ + NO3
Sb2O5 + HSO4 + NO in acidic solution
Cr202-7(aq) + C₂H5OH(1)→ Cr³+ (aq) + CO₂(g) in acidic solution
5.
-
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