Part I of the lab asks you to implement the following algorithm of converting an infix expression to a postfix expression using a stack of characters. Repeat the following for each element in an infix expression: • • If an operand is reached, append it to the postfix expression. If an open parentheses is reached, push it to the stack. If a close parenthesis is reached, pop the operators in the stack and append them to the postfix expression until an open parenthesis is popped. • If an operator is reached, pop the operators in the stack that are of higher or equal precedence than the new operator and append them to the postfix expression. After that, push the new operator to the stack. When the end of the infix expression is reached, pop and append the remaining operators in the stack and append them to the postfix expression

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
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C++ help please

Hi, I want to make this function from this link btu I want to do it without using c++ stack stack<char> st (built in stack), is it possible?

https://www.geeksforgeeks.org/convert-infix-expression-to-postfix-expression/

 

**Algorithm for Converting an Infix Expression to a Postfix Expression Using a Stack**

The goal of this part of the lab is to implement an algorithm that converts an infix expression to a postfix expression using a stack of characters. This process involves several key steps, as outlined below:

1. **Operand Handling**: 
   - If an operand is encountered, immediately append it to the postfix expression.

2. **Open Parenthesis Handling**:
   - Upon encountering an open parenthesis, push it onto the stack.

3. **Close Parenthesis Handling**:
   - When a close parenthesis is reached, repeatedly pop operators from the stack and append them to the postfix expression. This continues until an open parenthesis is popped from the stack.

4. **Operator Handling**:
   - For an operator, pop operators from the stack and append them to the postfix expression if they have higher or equal precedence compared to the current operator. Once complete, push the new operator onto the stack.

5. **End of Expression**:
   - After reaching the end of the infix expression, pop all remaining operators from the stack and append them to the postfix expression.

This step-by-step approach ensures the conversion of infix expressions, which are easier for humans to understand, into postfix expressions, which are more suitable for computer parsing and evaluation.
Transcribed Image Text:**Algorithm for Converting an Infix Expression to a Postfix Expression Using a Stack** The goal of this part of the lab is to implement an algorithm that converts an infix expression to a postfix expression using a stack of characters. This process involves several key steps, as outlined below: 1. **Operand Handling**: - If an operand is encountered, immediately append it to the postfix expression. 2. **Open Parenthesis Handling**: - Upon encountering an open parenthesis, push it onto the stack. 3. **Close Parenthesis Handling**: - When a close parenthesis is reached, repeatedly pop operators from the stack and append them to the postfix expression. This continues until an open parenthesis is popped from the stack. 4. **Operator Handling**: - For an operator, pop operators from the stack and append them to the postfix expression if they have higher or equal precedence compared to the current operator. Once complete, push the new operator onto the stack. 5. **End of Expression**: - After reaching the end of the infix expression, pop all remaining operators from the stack and append them to the postfix expression. This step-by-step approach ensures the conversion of infix expressions, which are easier for humans to understand, into postfix expressions, which are more suitable for computer parsing and evaluation.
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