Part H Calculate the oxidation number of the atom S according to the Lewis structure in Part G. Express your answer as a signed integer. Submit Request Answer Part I Calculate the oxidation number of the atom O according to the Lewis structure in Part G. Express your answer as a signed integer. Submit Request Answer
Part H Calculate the oxidation number of the atom S according to the Lewis structure in Part G. Express your answer as a signed integer. Submit Request Answer Part I Calculate the oxidation number of the atom O according to the Lewis structure in Part G. Express your answer as a signed integer. Submit Request Answer
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Part H and I are separate questions
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Since the molecule has a charge of 2-, two additional electrons should be added to the total number of valence electrons because both oxygen and sulfur are in group 6A (16) and contribute six electrons (e) each.
valence e in SO32- = (e contributed by S) + (e contributed by O) + (charge on molecule) = (1 x 6) + (3 × 6) +2 = 26 e
Since sulfur is less electronegative than oxygen, start by placing it as the central atom. Connect all atoms with single bonds, and then place lone pairs of electrons. Since all octets are complete, this is the final Lewis structure. Once the
electrons are properly placed, calculate the formal charge on each atom. The sum of the formal charges should equal the charge on the molecule, which is 2-.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F59db96a8-b0ec-4738-8e10-a8a69111bb88%2Fe14fef30-8d95-4223-b509-41b6ae8d3f3c%2Fw70toql_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Previous Answers
All attempts used; correct answer displayed
Since the molecule has a charge of 2-, two additional electrons should be added to the total number of valence electrons because both oxygen and sulfur are in group 6A (16) and contribute six electrons (e) each.
valence e in SO32- = (e contributed by S) + (e contributed by O) + (charge on molecule) = (1 x 6) + (3 × 6) +2 = 26 e
Since sulfur is less electronegative than oxygen, start by placing it as the central atom. Connect all atoms with single bonds, and then place lone pairs of electrons. Since all octets are complete, this is the final Lewis structure. Once the
electrons are properly placed, calculate the formal charge on each atom. The sum of the formal charges should equal the charge on the molecule, which is 2-.
![Part H
Calculate the oxidation number of the atom S according to the Lewis structure in Part G.
Express your answer as a signed integer.
Submit
Request Answer
Part I
Calculate the oxidation number of the atom O according to the Lewis structure in Part G.
Express your answer as a signed integer.
Submit
Request Answer](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F59db96a8-b0ec-4738-8e10-a8a69111bb88%2Fe14fef30-8d95-4223-b509-41b6ae8d3f3c%2Fftcdmk_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Part H
Calculate the oxidation number of the atom S according to the Lewis structure in Part G.
Express your answer as a signed integer.
Submit
Request Answer
Part I
Calculate the oxidation number of the atom O according to the Lewis structure in Part G.
Express your answer as a signed integer.
Submit
Request Answer
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