Part E What is the cell potential for the reaction at 57 °C when [Fe2+] = 2.90 Mand [Mg2+] = 0.210 M. Express your answer to three significant figures and include the appropriate units. ►View Available Hint(s) E = μA Value Units Mg(s)+Fe2+ (aq)→Mg2+ (aq) + Fe(s) ?
Part E What is the cell potential for the reaction at 57 °C when [Fe2+] = 2.90 Mand [Mg2+] = 0.210 M. Express your answer to three significant figures and include the appropriate units. ►View Available Hint(s) E = μA Value Units Mg(s)+Fe2+ (aq)→Mg2+ (aq) + Fe(s) ?
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![+ Introduction to the Nernst Equation
Learning Goal:
To learn how to use the Nernst equation.
The standard reduction potentials listed in any reference table are only
valid at the common reference temperature of 25 °C and standard
conditions of 1 M for solutions and 1 atm for gases. To calculate the
cell potential at nonstandard conditions, one uses the Nernst equation,
2.303 RT
E = E
nF
-log10 Q
where E is the potential in volts, E is the standard potential at 25 °C
in volts, R = 8.314 J/(K-mol) is the gas constant, T is the
temperature in kelvins, n is the number of moles of electrons
transferred, F = 96, 500 C/(mol e) is the Faraday constant, and
Qis the reaction quotient.
At the common reference temperture of 298 K, substituting each
constant into the equation the result is
E = E°
0.0592 V
n
log10
Q](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd28bb5a8-7114-481e-95e9-134d2c6aa143%2Fc9ffb854-7eda-404d-aab2-8f19d42dcbd1%2Flwma4v_processed.jpeg&w=3840&q=75)
Transcribed Image Text:+ Introduction to the Nernst Equation
Learning Goal:
To learn how to use the Nernst equation.
The standard reduction potentials listed in any reference table are only
valid at the common reference temperature of 25 °C and standard
conditions of 1 M for solutions and 1 atm for gases. To calculate the
cell potential at nonstandard conditions, one uses the Nernst equation,
2.303 RT
E = E
nF
-log10 Q
where E is the potential in volts, E is the standard potential at 25 °C
in volts, R = 8.314 J/(K-mol) is the gas constant, T is the
temperature in kelvins, n is the number of moles of electrons
transferred, F = 96, 500 C/(mol e) is the Faraday constant, and
Qis the reaction quotient.
At the common reference temperture of 298 K, substituting each
constant into the equation the result is
E = E°
0.0592 V
n
log10
Q
![▼
Was either rounded differently or used a different number of significant figure
Although the reaction given in the introduction is at an elevated temperature, the standard cell potential at 25 °C is used in
potential under non-standard conditions.
Part E
What is the cell potential for the reaction
E =
at 57 °C when [Fe²+] =
= 2.90 M and [Mg2+] =
= 0.210 M
Express your answer to three significant figures and include the appropriate units.
►View Available Hint(s)
Submit
μÅ
Value
Provide Feedback
Units
Mg(s) + Fe2+ (aq)→Mg2+ (aq) + Fe(s)
?](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd28bb5a8-7114-481e-95e9-134d2c6aa143%2Fc9ffb854-7eda-404d-aab2-8f19d42dcbd1%2Fb4m9aab_processed.jpeg&w=3840&q=75)
Transcribed Image Text:▼
Was either rounded differently or used a different number of significant figure
Although the reaction given in the introduction is at an elevated temperature, the standard cell potential at 25 °C is used in
potential under non-standard conditions.
Part E
What is the cell potential for the reaction
E =
at 57 °C when [Fe²+] =
= 2.90 M and [Mg2+] =
= 0.210 M
Express your answer to three significant figures and include the appropriate units.
►View Available Hint(s)
Submit
μÅ
Value
Provide Feedback
Units
Mg(s) + Fe2+ (aq)→Mg2+ (aq) + Fe(s)
?
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