Part D What is the magnitude of the resultant acceleration of a point on the tip of the blade at time t 0.200 s ? m/s You have already submitted this answer. Enter a new answer. No credit lost. Try again. Submit Previous Answers Request Answer
Part D What is the magnitude of the resultant acceleration of a point on the tip of the blade at time t 0.200 s ? m/s You have already submitted this answer. Enter a new answer. No credit lost. Try again. Submit Previous Answers Request Answer
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Compute the angular velocity alter a time of 0.200 s.
An electric turntable 0.780 m in diameter is rotating about a fixed axis with an
W = 0.423 rev/s
initial angular velocity of 0.240 rev/s. The angular acceleration is 0.917 rev/s2 .
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Prevlous Answers
v Correct
Important: If you use this answer in later parts, use the full unrounded value in your calculations.
Part B
Through how many revolutions has the blade turned in this time interval?
N = 6.63x102 rev
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Part C
What is the tangential speed of a point on the tip of the blade at time t 0.200 s ?
%3D
v = 1.04 m/s
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Part D
%3D
What is the magnitude of the resultant acceleration of a point on the tip of the blade at time t = 0.200 s ?
ΑΣφ
11 ?
m/s?
a 3=
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Transcribed Image Text:UCI CareerToolkit202 X
Calendar
Course Home
9The Revolt of th
Mox (517) - mej X
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openvellum.ecollege.com/course.html?courseld%317313546&OpenVellumHMAC%3D1421cec11b68967er
fic0be179cc443d#10001
Compute the angular velocity alter a time of 0.200 s.
An electric turntable 0.780 m in diameter is rotating about a fixed axis with an
W = 0.423 rev/s
initial angular velocity of 0.240 rev/s. The angular acceleration is 0.917 rev/s2 .
Submit
Prevlous Answers
v Correct
Important: If you use this answer in later parts, use the full unrounded value in your calculations.
Part B
Through how many revolutions has the blade turned in this time interval?
N = 6.63x102 rev
Previous Answers
v Correct
Part C
What is the tangential speed of a point on the tip of the blade at time t 0.200 s ?
%3D
v = 1.04 m/s
Submit
Previous Answers
v Correct
Part D
%3D
What is the magnitude of the resultant acceleration of a point on the tip of the blade at time t = 0.200 s ?
ΑΣφ
11 ?
m/s?
a 3=
You have already submitted this answer. Enter a new answer.
No credit lost. Try again.
Submit
Previous Answers Request Answer
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