Part C Learning Goal: To understand and apply the formula T = Ia to rigid objects rotating about a fixed axis. To find the acceleration a of a particle of mass m, we use Newton's second law: F mã, where Fnet is the net force acting on the net = particle. To find the angular acceleration a of a rigid object rotating about a fixed axis, we can use a similar formula: Tnet = = Ia, where Tnet = T is the net torque acting on the object and I is its moment of inertia. Now consider a similar situation, except that now the swing bar itself has mass mbar = 2.1 kg. The center of the mass of the bar is at its center, where the pivot is located. (Figure 2) Find the magnitude of the angular acceleration a of the seesaw. Express your answer numerically, keep 3 digits after the decimal point, in rad/s² ▸ View Available Hint(s) 肪 ΜΕ ΑΣΦΑ ? Figure #1 mbar 9822 new case swing bas has mass a = < 2 of 2 Submit Previous Answers × Incorrect; Try Again; 5 attempts remaining Part D In what direction will the seesaw rotate and what will the sign of the angular acceleration be? The rotation is in the clockwise direction and the angular acceleration is positive. The rotation is in the clockwise direction and the angular acceleration is negative. rad/s²

Part C Learning Goal: To understand and apply the formula T = Ia to rigid objects rotating about a fixed axis. To find the acceleration a of a particle of mass m, we use Newton's second law: F mã, where Fnet is the net force acting on the net = particle. To find the angular acceleration a of a rigid object rotating about a fixed axis, we can use a similar formula: Tnet = = Ia, where Tnet = T is the net torque acting on the object and I is its moment of inertia. Now consider a similar situation, except that now the swing bar itself has mass mbar = 2.1 kg. The center of the mass of the bar is at its center, where the pivot is located. (Figure 2) Find the magnitude of the angular acceleration a of the seesaw. Express your answer numerically, keep 3 digits after the decimal point, in rad/s² ▸ View Available Hint(s) 肪 ΜΕ ΑΣΦΑ ? Figure #1 mbar 9822 new case swing bas has mass a = < 2 of 2 Submit Previous Answers × Incorrect; Try Again; 5 attempts remaining Part D In what direction will the seesaw rotate and what will the sign of the angular acceleration be? The rotation is in the clockwise direction and the angular acceleration is positive. The rotation is in the clockwise direction and the angular acceleration is negative. rad/s²

Similar questions

A high-speed drill reaches 2500 rpm in 0.50 s. Part A What is the drill's angular acceleration? Express your answer in radians per second squared. 7VE ΑΣΦ α= Submit rad/s² You have already submitted this answer. Enter a new answer. No credit lost. Try again. Part B 0 = Previous Answers Request Answer ? Through how many revolutions does it turn during this first 0.50 s? Express your answer in revolutions. Π ΑΣΦ ? rev
The 5-kg cylinder is initially at rest when it is placed in contact with the wall B and the rotor at A. Part A If the rotor always maintains a constant clockwise angular velocity w = 6 rad/s, determine the initial angular acceleration of the cylinder. The coefficient of kinetic friction at the contacting surfaces B and C is uk = 0.2. (Figure 1) Express your answer with the appropriate units. ? a = Value Units Submit Request Answer Figure 1 of 1 Provide Feedback Next > 125 mm 45 P Pearson
A 0.74-m-diameter solid sphere can be rotated about an axis through its center by a torque of 12.8 m * N which accelerates it uniformly from rest through a total of 160 revolutions in 16.0 s. Part A What is the mass of the sphere? Express your answer to two significant figures and include the appropriate units. M = O μA Submit Value Units Request Answer ?
A child exerts a tangential 55.1 N force on the rim of a disk-shaped merry-go-round with a radius of 2.39 m. Part A If the merry-go-round starts at rest and acquires an angular speed of 0.4250 rev/s in 5.00 s, what is its mass?
Problem 7 : A sphere of radius r0 = 24.0 cm and mass m = 1.20kg starts from rest and rolls without slipping down a 33.0∘ incline that is 15.0 m long. Part A Calculate its translational speed and rotational speed when it reaches the bottom. Does the answers depend on mass or radius of the ball? Part C What is the ratio of translational to rotational kinetic energy at the bottom?(Ktr/Krot=?) Does the answer depend on mass or radius of the ball?
A lawn mower has a flat, rod-shaped steel blade that rotates about its center. The mass of the blade is 0.65 kg and its length is 0.55 m. You may want to review (Pages 314 - 318). Part A What is the rotational energy of the blade at its operating angular speed of 3460 rpm ? Express your answer using two significant figures. Kr= Submit Part B v Templates Symbols undo redo reset keyboard shortcuts help y = Request Answer If all of the rotational kinetic energy of the blade could be converted to gravitational potential energy, to what height would the blade rise? Express your answer using two significant figures. J Templates Symbols undo redo reset keyboard shortcuts help m
The angular speed of a propeller on a boat increases with constant acceleration from 14 rad/srad/s to 35 rad/srad/s in 2.6 revolutions. Part A What is the angular acceleration of the propeller? Express your answer in radians per second squared.
Cons A constant torgue of 25 m - N is applied to the rim of a 15-kg uniform disk of radius 0.30 m. Part A What is the angular speed of the disk about an axis through its center after it rotates 2.0 revolutions from rest? Express your answer using two significant figures. Ην ΑΣφ rad/s Previous Answers Request Answer Submit X Incorrect; Try Again; 5 attempts remaining
A rotating door is made from four rectangular glass panes, as shown in the figure. The mass of each pane is 94.8 kg. A person pushes on the outer edge of one pane with a force of F = 71.7 N that is directed perpendicular to the pane. Determine the magnitude of the door's angular acceleration. 1.2 m 1.2 m Number i Units
A merry-go-round accelerates from rest to 0.70 rad/s in 30 s. Part A Assuming the merry-go-round is a uniform disk of radius 8.0 m and mass 3.20×104 kg , calculate the net torque required to accelerate it. Express your answer to two significant figures and include the appropriate units.
A 2.6-m-diameter merry-go-round with rotational inertia 140 kg. m² is spinning freely at 0.60 rev/s. Four 25-kg children sit suddenly on the edge of the merry-go-round. Part A Find the new angular speed. Express your answer using two significant figures. V= for Part A for Part A undo for Part A redo for Part A reset for Part A keyboard shortcuts for Part A help for Part A Submit Part B Determine the total energy lost to friction between the children and the merry-go-round. Express your answer using two significant figures. AK = Request Answer Submit rev/s for Part B for Part B undo for Part B redo for Part B reset for Part B keyboard shortcuts for Part B help for Part B Request Answer J
A bicycle is rolling down a circular hill that has a radius of 7.49 m. As the figure illustrates, the angular displacement of the bicycle is 0.960 rad. The radius of each wheel is 0.449 m. What is the angle (in radians) through which each tire rotates? Number i Units rad